00:02
Okay, we're asked the number of nitrogen atoms in 1 .00 grams of everything number 39.
00:19
So let me get over to exercise 39 and see what this is about here.
00:29
35, 36, 37, 38, 39.
00:32
39 is nh3.
00:45
339.
00:46
And 39c is nh4 cr207.
00:55
Okay, for each of these, i'm given 1 .00 grams.
01:02
So i'm going to do this by, multiplying this by the molar mass, multiplying the moles by avagadro's number, molecules per mole, and writing one molecule of nh3 contains one atom of nh3.
01:39
This will give me, my calculator, i guarantee is going to die.
01:45
One times 6 .022 times 10 to the 23rd divided by 17 .0.
01:54
This should be 17 .03.
02:01
And that will equal 3 .54 times 10 to the 22nd atoms of n.
02:16
Very nice.
02:20
Let's see here.
02:25
And hang on just a sec.
02:35
So this is, what problem i'm working on? this is 49.
02:42
I make myself a note.
02:45
Okay...