00:01
This problem asks you to determine which orbitals are overlapping in order to form a bond, for instance, between carbon and beryllium, or between carbon and hydrogen for each of these three molecules.
00:11
The way to go about this problem is first to determine which orbitals are being used by which atoms.
00:18
So you want to figure out the hybridization.
00:21
Well, hydrogen only ever can contribute an s -orbital to orbital overlap.
00:27
Carbon in this case has four groups attached to it, meaning it's sp3 hybridized.
00:33
And borrelium in this case only has two bonds, therefore it's sp hybridized.
00:38
Then when you're looking at each individual bond, you can figure out what is actually overlapping, and that's your answer.
00:45
So, for instance, just to show you what the overlap looks like, are made of lobes coming off of each center of the carbon to make a tetrahedral.
00:52
That gets the four groups as far apart as possible, making it the most.
00:56
Stable and lowest in energy.
00:59
We can do the same thing for the other hydrogens, as well as for the beryllium carbon bond.
01:04
And i've just drawn that in green just because it's a different hybridized orbital.
01:09
So the carbon hydrogen bonds, all of them, all three of them, are made up of an s hydrogen orbital overlapping with a carbon sp3 orbital.
01:19
So the answer for say this bond is carbon sp3 overlap with hydrogen s.
01:26
You could also write that as well, hydrogen s overlapping with carbon and sp3.
01:30
But this is typically how we draw it.
01:33
If we look at the carbon beryllium bond, well, we have a carbon sp3 hybridized orbital overlapping with a beryllium sp hybridized orbital...