00:01
In this question, pkb of a weak base coding is given as 5 .80 and we have to calculate the ph of 0 .0 to 0 molar solution of coding.
00:14
We have to calculate this one.
00:15
Now first, pkb is given.
00:20
Pkb is 5 .80.
00:30
Now pkb means negative.
00:32
Negative log, negative log, kb is 5 .80.
00:40
Therefore, kb is 10 to the power negative 5 .80.
00:48
Therefore, kb is 1 .6 times 10 to the power negative 6.
00:56
Now, say hb is that weak base in aqua solution, it is in equilibrium with bh2 plus and oh minus.
01:20
Okay, let's make the ice table here.
01:26
Initial concentration 0 .02 to 00.
01:36
Change concentration minus x plus x plus x and equilibrium concentration is 0 .02 minus x x and x.
01:50
Now let's write the expression for kb divided by the concentration of the weak acid.
02:11
Now, kb is 1 .6 times 10 to the power negative 6.
02:23
Concentration of bh2 plus is x, h3o plus, sorry, it's not h3o plus, oh, is minus x times x, x squared, divided by 0 .02 minus x...