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This is the answer to chapter 3.
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Problem number 12 from the smith organic chemistry textbook.
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And this problem is asking us to draw the results, the product of two anionic polymerizations.
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And so remember, this relates to apocity.
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And the polymer -making bonds that we form are going to be carbon -oxygen bonds rather than carbon -carbon bonds.
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And so we should start by considering the epoxide that we're given.
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And so here is our monomer.
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This is the epoxide that we have for a.
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And we should think about what that's going to look like once it's opened.
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And from there, we can begin to get the answer.
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So the way that a lot of these answers look for these, this type of polymerization, is you just draw the central unit once in brackets with this n notation.
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So the lowercase n.
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And that basically just indicates that it's repeating as many times as you'd like.
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And so having drawn that, we then need to think about what our open -de -opoxide is going to look like.
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And so in this case, it's going to look like, oops, where'd that line go? in this case, it's going to look like this.
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And so it'll be a bond there.
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It will be a bond there.
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And so this central unit here is our open -de -opoxide.
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And again, it's in the end brackets.
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And so this means that it repeats, you know, indefinitely, and number of times.
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And then the only other thing we need to draw is what the two ends of this polymer are going to look like.
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So each of the ends of this polymer is just going to be another open -opoxide.
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But an opened epoxide with another hydroxy on it.
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Because remember hydroxy is going to open the epoxide to begin with to sort of kick this whole process off.
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And so our end pieces are going to have hydroxy functionality on them...