Question

What products would result from the following processes? Write an equation for each reaction. a. 1-Butanol is heated to $140^{\circ} \mathrm{C}$ in the presence of sulfuric acid. b. 1-Butanol is subjected to an excess of oxidizing agent. c. 2-Pentanol is subjected to controlled oxidation. d. 2-Pentanol is heated to $180^{\circ} \mathrm{C}$ in the presence of sulfuric acid. e. 2-Methyl-2-pentanol is subjected to controlled oxidation.

   What products would result from the following processes? Write an equation for each reaction.
a. 1-Butanol is heated to $140^{\circ} \mathrm{C}$ in the presence of sulfuric acid.
b. 1-Butanol is subjected to an excess of oxidizing agent.
c. 2-Pentanol is subjected to controlled oxidation.
d. 2-Pentanol is heated to $180^{\circ} \mathrm{C}$ in the presence of sulfuric acid.
e. 2-Methyl-2-pentanol is subjected to controlled oxidation.
Show more…
Chemistry for Today: General, Organic, and Biochemistry
Chemistry for Today: General, Organic, and Biochemistry
Spencer L. Seager,… 10th Edition
Chapter 13, Problem 47 ↓

Instant Answer

verified

Step 1

The reaction can be represented as follows: \[ \text{C}_4\text{H}_{10}\text{O} \xrightarrow{\text{H}_2\text{SO}_4, \Delta} \text{C}_4\text{H}_8 + \text{H}_2\text{O} \] The product is butene (C₄H₈).  Show more…

Show all steps

lock
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
What products would result from the following processes? Write an equation for each reaction. a. 1-Butanol is heated to $140^{\circ} \mathrm{C}$ in the presence of sulfuric acid. b. 1-Butanol is subjected to an excess of oxidizing agent. c. 2-Pentanol is subjected to controlled oxidation. d. 2-Pentanol is heated to $180^{\circ} \mathrm{C}$ in the presence of sulfuric acid. e. 2-Methyl-2-pentanol is subjected to controlled oxidation.
Close icon
Play audio
Feedback
Powered by NumerAI
*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Oxidation Resistance of Tertiary Alcohols
Tertiary alcohols are resistant to oxidation under mild conditions because the carbon atom bearing the hydroxyl group does not have a hydrogen attached. Without an available hydrogen to be removed during the oxidation process, these compounds do not form carbonyl derivatives, making them inert to many standard oxidizing agents.
Oxidation of Secondary Alcohols
Secondary alcohols are typically oxidized to ketones under controlled oxidation conditions. This transformation involves the removal of two hydrogen atoms, one from the hydroxyl-bearing carbon and one from the oxygen, resulting in the formation of a carbonyl group. The process is generally straightforward because the carbon skeleton remains intact.
Oxidation of Primary Alcohols
Primary alcohols can be oxidized in a stepwise manner: first to an aldehyde and then, if excess oxidizing agent is present, further to a carboxylic acid. The reaction involves the removal of hydrogen atoms from the alcohol, and control over the reaction conditions (such as the amount of oxidant) determines whether the oxidation stops at the aldehyde stage or continues to form the acid.
Acid?Catalyzed Dehydration of Alcohols
This process involves the elimination of water from an alcohol in the presence of an acid catalyst to form an alkene. The mechanism typically involves protonation of the hydroxyl group, conversion into a better leaving group, and the subsequent loss of water to form a carbocation intermediate which then loses a proton to yield the alkene. The reaction often follows Zaitsev’s rule, favoring the formation of the more substituted, and therefore more stable, alkene.

*

Recommended Videos

-
329what-products-would-result-from-the-following-processes-write-an-equation-for-each-reaction-_-a-1-butanol-is-heated-to-140c-in-the-presence-of-sulfuric-acid-b-1-butanol-is-subjected-to-an-65725

Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever