Question
What radius must a water drop have for the difference between the inside and outside pressures to be 0.0200 atm? The surface tension of water is 72.8 dynes/cm.
Step 1
We know that 1 atmosphere is equal to 1.013 x 10^5 pascals. Therefore, the pressure difference in pascals is given by: \[ \Delta P = 0.0200 \times 1.013 \times 10^5 \] Show more…
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What radius must a water drop have for the difference between the inside and outside pressures to be $0.0200 \mathrm{~atm} ?$ The surface tension of water is $0.0728 \mathrm{~N} / \mathrm{m}$
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