00:02
This is the answer to chapter 3, problem number one, from the smith organic chemistry textbook.
00:09
And in this problem, we're asked what happens when we treat ethanol with sodium hydride or with sulfuric acid? and then we're asked what happens if we treat ethane with those same reagents.
00:26
And so from chapter two, hopefully you remember that ethanol, the oh can give up that proton to a strong base or the oxygen can take on another proton if it's treated with a strong acid.
00:47
And so that's what's going to happen here.
00:49
So when we treat ethanol with sodium hydride, the hydride is going to grab the proton.
01:00
And so the oxygen is going to have three lone pairs and a negative charge, and then we'll have a sodium ion from sodium hydride that's going to be attracted to that negatively charged oxygen, and then we'll also have hydrogen gas.
01:24
And so when ethanol is treated with sulfuric acid, what we get is the oxygen, gets protonated.
01:38
So the oxygen now has two hydrogens.
01:42
It only has one lone pair, and it has a positive charge, and then we'll also get h .s .o .4 with a negative charge.
01:58
Okay.
01:59
And so when we treat ethane with either of these reagents, there is no reaction...