00:02
In this problem, we have an rlc circuit, where the inductance is equal to 220 millie henries, the capacitance is equal to 12 micropharats, and we have to find the resistance such that the charge decays to 99 % of its initial value in 50 periods.
00:44
So our first step is that the charge decays to 99 % of its initial value in 50 periods.
00:47
We need to find the time required to do 50 cycles.
01:02
Now we know that the periods, the period of an rlc circuit is equal to 2 pi over the angular frequency, which is equal to 2 pi times the square root of the inductance, times the capacitance.
01:17
So this is equal to 2 pi times the square root of 220 milligenries times 12 micropharats.
01:43
And this period.
01:45
Is equal to, and then we actually need the time for 50 cycles, so we actually need 50 times this period.
01:53
So turns out that this time is equal to 0 .51 .04 seconds.
02:02
Then we need to know by how much the charge decays in that time...