We can use the formula $Q = mc\Delta T$, where $m$ is the mass of the water, $c$ is the specific heat of water, and $\Delta T$ is the change in temperature.
Given that $m = 500 \mathrm{~g} = 0.5 \mathrm{~kg}$, $c = 1000 \mathrm{~cal/kg \cdot C}$, and $\Delta T =
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