what-type-of-radiation-has-a-wavelength-of-612-times-102-mathrmm-2

Question

What type of radiation has a wavelength of $6.12 	imes 10^{2} \mathrm{m} ?$

Vishal Sharma · Accepted Answer

in problem for which type off relation has wavelength off 6.1 to 10 days to power to meter. So the radio waves help prevalent in the range off in the range off 6.12 and 2 10 days to power 2 m. Because radio waves exactly wavelength is radio waves equivalent that is three into 10 days to power. 3 m and its frequency is 10 days to power. Five hearts. Yeah. So that means we can say that this Waveland that is given in the ocean 6.12 into 10 list power to meter have is having the range off the radio waves.

Allen Yesin · Answer

Oh, right. So we&#x27;re going to be solving this problem where first we will be finding the frequency of on the electromagnetic creation, and then we will be identifying what type it is, and we&#x27;ll be using this E m g radiation spectrum. Ah, to be doing that. So first, what we will be doing is we&#x27;ll be using our equation that we know that&#x27;s the relation between wave length and frequency, which is Lambda Nu equals C. Uh, Lambda is the Greek letter that&#x27;s going to do know our wavelength and just a reminder wavelength is the distance. So if we have our wave right here, it&#x27;s the distance from a peak to a peak. So distance right here or from a crest to another crust like this. That&#x27;s what our way of link with, uh would be Then new is our Greek letter that we do know frequency, frequency and frequency is the cycles that waves. So how many times this will occur in one second? So a high frequency wave would look probably something like this and a lower frequency way of my looks, something like this. Anyway, so ah will be using dis equation right here and what is see my US That is actually our speed of light, which we know that&#x27;s not gonna change. That&#x27;s 2.998 times 10 to the ace, meters per seconds. That&#x27;s gonna be our speed of light. Okay, so now we&#x27;re just going to use this equation, Rearranges a little bit, And that way we&#x27;ll be able to solve for our frequency. So by rearranging this question this equation we get new equals c over lambda. Just by rearranging, that&#x27;s we have frequency equals the speed of light over the wavelength. So that way we have new eagles 2.998 times, 10 to the meters per second and divide that by 3.3 three times 10 to the negative eighth meters. And from that, we are going to get a wavelength. Are Sorry. We&#x27;re going to get our frequency. Uh, which is 9.1 times 10 to the 15th hurts. And so then we take this information right here. We&#x27;re gonna go here. We&#x27;re gonna apply it. Ah too. Our e m g spectrum. So on the M G spectrum, we have our highest frequency. Ah, we&#x27;re sorry. Our lowest frequency waves on this side and our highest frequency waves on the sets. On this side, we have our gamma rays, which would probably look like this very high frequency, very low wavelength. Right. And then over here we have our radio waves would probably look something like that. Huge waves, big distance, very low frequency. And so right here we see that we have tend to the 15th hurts, so tend to the 15. The herds is going to reside somewhere right here. And if we remember, visible light is not really an actual type of light wave. It&#x27;s actually just the portion on the E m G radiation spectrum in which we can actually see the waves. So if we&#x27;re looking here, will see that that resides about right here with you ve So this frequency is the frequency of you ve radiation

Keenan Mintz · Answer

So now we&#x27;ll work on problem 46 from chapter five. He rest about the wavelength of radiation with the frequency of 5.0 times 10 to the 12 hurt JJ. So we won&#x27;t know the wavelength. And we also want to know what kind of radiation it ISS. So we know that we can relate Frequency toe wavelength through the speed of light. C equals to land a new. So we can rearrange this here to solve for Lambda wavelength by dividing the speed of light by new or frequency. So the speed of light is 2.998 times 10 to the eighth meter per second. And then we put in our frequency, which is what we&#x27;re given 5.0 times 10 to the 12th hurts or seconds minus one. We do this calculation, we get a value of 6.0 times 10 to the negative fifth meters. So if we were to look at the spectrum the sort of range that were given in the book for either frequency or wavelength, we can check either with this value or this value, we can see that either of these values falls into the infrared region of the electromagnetic radiation range. And so it&#x27;s infrared light

Sheh Lit Chang · Answer

in this question. Uh, we wants to identify the electromagnetic wave that has replaying or the size of an atom. Okay, so the size off and Adam is typically attended Afghanistan meters. So, um, the bees under electoral man Eddie spectral, uh, X rays, huh? With length off the order tend to the negative 10 meters. So this is the answer.

Tim Blackstad · Answer

Okay, Well, this question is asking What is the wavelength of energy associated with a compound that has 1000 killer jewels per mole of energy? And and what range or what area of the electromagnetic spectrum it is in. So we can go ahead and start by saying 1000 killer jewels is equal to one million jewels because we know there&#x27;s 1000 jewels and every killer jewel. Okay, I will say 1.0 times 10 in the sixth jewels. Permal. Okay. And we know that the energy, the equation that relates energy and frequency and wavelength, is energy of a photon and or other let giving thing is able to plank&#x27;s constant times of frequency. Okay, so we know that this is for an individual electron photon something or Adam. Okay, so we need to go ahead and it&#x27;s in. Find the energy associated with one molecule. Were Adam instead of one mole. So we will divide by avocados number, which is six point 0 to 2 times 10 to the 23rd. This is how maney particles are molecules in one mole of a substance. So this is going to give us 1.66 times 10 to the negative. 18th Jules Permal. Their jewels per molecule. Excuse me. So now that we have that we this is we can use this as the energy in this equation. Jules. Per we&#x27;ll sit, Adam, so we don&#x27;t get confused. So you go ahead and put this in as 1.66 charms. 10 to the 18th equals place constant, which is 6.63 times 10 to the negative. 34th joules per second times the frequency. Hey, and this is what we&#x27;re looking for. So when we saw for frequency, we get that the frequency is equal to it is equal to 2.5 times 10 to the 15 hurts. So when we plug this into the equation that relates frequency and wavelength, where wavelength is equal to speed, what defined by frequency we would get that is equal to three times 10 to the eighth, which we notice the speed of light constant meters per second. Divided by we just found as it&#x27;s we just found is the frequency. There&#x27;s 2.5 times 10. True, the 15th hurts. We&#x27;re going to get the wavelength to be 1.2 times 10 to the negative seventh meters which we can also convert two nanometers, which we know would be 100 29 years now the this would put it in the ultraviolet range. UV range is between 10 mana meters and 400 nanometers. This is just just lower. They&#x27;re just the wavelength of this light is just low earth in the visible three of the visible spectrum which is just so we know that since it is obviously in between 10 animators and 400 a meters, the wavelength of this light given off is in the UV spectrum and has a specific wavelength of 120 nanometers.

Stephanie L · Answer

So in this question, we I asked for the leave length, and what we&#x27;re given is the energy and specifically were given the energy and kill jobs program. So if you think about how we&#x27;re gonna get the wavelength, the only equation that relates energy toe wavelength is the equation. E float on. The energy of a single full time is equal to agency over land up where h is Planck&#x27;s constant and C is the speed of light. Now this energy, he is in jewels, and it&#x27;s just for a single for the time. So the first thing that we have to do before you can use this equation and find the wavelength is we have to convert this energy into the energy and jewels of just a single photons. So if we start first with converting the killing journalists, Digital&#x27;s No. One killer, Jewell 1000 jewels, it&#x27;s in their other killjoys cancels. But then we have the rule at the bottom. I was free righted, it&#x27;s clear, and that&#x27;s ah, full of photons, right? So if you want to get rid of that, we need a poll on hearing on top. Here s a little and in one mole of photons. Just like anything you have 61 to 2. I was sent in 23 of that pink in this gives photons. Yes. If we look at our units, walls will cancel I and we&#x27;ll be left with chills. You&#x27;re full time. And so when we enter that in the calculator, what we get is we planned for I am still to the negative 18 Charles puts on. So now we can use this equation to get from the energy of one photons to the wavelength. And if so, free rearranges we get old. Amanda equals H c. Over the energy of one full time is the ages plants constant engine 6.63 I was sensitive and they&#x27;re, you know, 34 jewel. Second c is the speed of lights. 3.0 time stands in the eight meters per second and the unity of the photon is what we calculated some 3.54 I understand that negative 18 jewels never remove the full time. Just goes that&#x27;s not any chance without and do that we get by a plane. 62 I was sensitive negative eight meters. Now they want the wavelength in nanometers, So you convert that to centimeters. I think it&#x27;s cute times that anything new uterus in one meter we had since the night una meters. And so that gives us 56 points to banana meters. Now, the wavelength reach for the visible spectrum is 400 to 700. Are you so this is lower than that. And so this falls in the UV rich and the U The range of the electromagnetic spectrum on is around 10 centimeters, 400 nanometers, so that falls in there.

Problem

Identify an object that is similar in size to the…

Problem 4 Easy Difficulty

What type of radiation has a wavelength of $6.12 \times 10^{2} \mathrm{m} ?$

Answer

Radio waves have wave length in the range of $6.12 \times 10^{2}$ $\mathrm{m}$

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Radio waves have wave length in the range of $6.12 \times 10^{2}$ $\mathrm{m}$

Living by Chemistry

Stephen P.

Allea C.

Morgan S.

Jake R.

Liquids - Intro

Comparison Of Gases Liquids And Solids

Angelica M. StacyLiving by Chemistry

Stephen P.

Allea C.

Morgan S.

Jake R.

Angelica M. Stacy

Living by Chemistry