Question

What volume (in milliliters) of 0.245 M HCl will neutralize 50.0 mL of $0.100 \mathrm{M} \mathrm{Ca}(\mathrm{OH})_2$ ? The equation is $$ 2 \mathrm{HCl}(a q)+\mathrm{Ca}(\mathrm{OH})_2(a q) \longrightarrow \mathrm{CaCl}_2(a q)+2 \mathrm{H}_2 \mathrm{O}(l) $$

Name: Problem 24, Chapter 15: Foundations of College Chemistry
Uploaded: 2021-05-03T14:04:31-08:00
Duration: 1 min 17 s
Channel: David Collins
Description: What volume (in milliliters) of 0.245 M HCl will neutralize 50.0 mL of 0.100 M Ca(OH)2 ? The equation is 2 HCl(a q)+Ca(OH)2(a q) ⟶CaCl2(a q)+2 H2 O(l)

   What volume (in milliliters) of 0.245 M HCl will neutralize 50.0 mL of $0.100 \mathrm{M} \mathrm{Ca}(\mathrm{OH})_2$ ? The equation is
$$
2 \mathrm{HCl}(a q)+\mathrm{Ca}(\mathrm{OH})_2(a q) \longrightarrow \mathrm{CaCl}_2(a q)+2 \mathrm{H}_2 \mathrm{O}(l)
$$

Foundations of College Chemistry

Morris Hein, Susan… 12th Edition

Chapter 15, Problem 24

Instant Answer

Solved by Expert David Collins

05/03/2021

Step 1

The equation is: $$ 2 \mathrm{HCl}(aq) + \mathrm{Ca(OH)}_2(aq) \longrightarrow \mathrm{CaCl}_2(aq) + 2 \mathrm{H}_2 \mathrm{O}(l) $$ Show more…

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What volume (in milliliters) of 0.245 M HCl will neutralize 50.0 mL of $0.100 \mathrm{M} \mathrm{Ca}(\mathrm{OH})_2$ ? The equation is $$ 2 \mathrm{HCl}(a q)+\mathrm{Ca}(\mathrm{OH})_2(a q) \longrightarrow \mathrm{CaCl}_2(a q)+2 \mathrm{H}_2 \mathrm{O}(l) $$

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Key Concepts

Molarity

Molarity is the concentration of a solution expressed in moles of solute per liter of solution. It is a fundamental concept used to determine the number of moles present in a given volume of solution, which is essential for performing quantitative chemical calculations in reactions.

Stoichiometry

Stoichiometry involves understanding the quantitative relationships between reactants and products in a chemical reaction. It uses the coefficients from the balanced chemical equation to determine how many moles of one substance are needed to react completely with a given number of moles of another substance.

Acid-Base Neutralization

Acid-base neutralization is a type of chemical reaction where an acid reacts with a base to form water and a salt. The process relies on the stoichiometric relationship between the acidic and basic species, and it is fundamental in titration techniques used to determine the concentration of unknown solutions.

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