00:02
For this question, let's start with our balanced redox equation.
00:07
We have cr2 -07 -2 -minus reacting with i -minus to produce chromium 3 plus and iodine.
00:20
We break this apart into two separate half reactions and balance separately.
00:26
We have cr2 -07 -2 -minus to chromium 3 plus, 2 to balance.
00:33
The chromium, 7h2o to balance the oxygen, 14h plus to balance the hydrogen, and to balance the charge, 6 electrons.
00:49
Second half reaction, i minus to i2, 2 to balance the iodine, 2 electrons to balance the charge, multiply this half reaction by 3 and this half reaction by 1, or a common multiple for the electrons, 6 electrons, 14h plus, cr2072 minus, 3 plus, 7h20, 6i minus, 3i2, 6e2, 6 electrons, electrons will cancel, a balanced redox equation, cr2222 minus, 6i minus, 14h plus, 2 chromium 3 plus, 3i2, and 7h2o.
01:40
In this question, we're told that we have 0 .190 molar potassium dichromate.
01:52
That would be our dichromate malarity...