What volume of 0.250 M H2 SO4 is needed to react with 50.0 mL of 0.100 M NaOH ? The equation is

What volume of 0.250 M H2 SO4 is needed to react with 50.0...

What volume of $0.250 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}$ is needed to react with $50.0 \mathrm{~mL}$ of $0.100 \mathrm{M} \mathrm{NaOH}$ ? The equation is $$\mathrm{H}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{NaOH}(a q) \longrightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)$$

Key Concepts

Molarity

Molarity is defined as the number of moles of a solute per liter of solution. It is used to determine the amount of substance present in a given volume of solution, making it critical for calculations in reactions involving solutions.

Balanced Chemical Equations

A balanced chemical equation shows the complete reaction with the correct stoichiometric coefficients for all reactants and products. This ensures the conservation of mass and allows for the calculation of the precise mole ratios needed for reaction calculations.

Stoichiometry

Stoichiometry involves the quantitative analysis of reactants and products in a chemical reaction based on the mole relationships derived from the balanced chemical equation. It enables the determination of how much of one substance is needed to react completely with a given amount of another substance.

Acid-Base Neutralization

Acid-base neutralization is a reaction where an acid reacts with a base to form water and a salt. Understanding this process is essential for calculating the volumes and concentrations needed for complete neutralization in titration and other related chemical reactions.

Transcript

00:01 In this problem, we're given the following acid -based reaction and some information about the two reactants.

00:09 Ultimately, our goal is to find the volume of sulfuric acid.

00:19 Now, when it comes to molarity, we have to remember the definition of molarity given by the m is moles divided by volume in liters.

00:32 So notice that this is a three variable equation.

00:36 If you know two of these, you can find the third using algebra.

00:42 If you know these two, you can find that one, etc.

00:48 So starting with naoh, notice that we have molarity and volume.

00:54 So we know two of the three variables.

00:56 We can use that to find moles.

00:59 So that's going to be our first step.

01:03 Find moles of naoh.

01:06 That's the substance that i know the most about.

01:10 Next, what i'll do is i'll use my mole -to -mole ratios.

01:13 Remember there's the secret one right there to convert that information into moles of sulfuric acid.

01:24 So that would be sub -2, is to use mole -to -mole ratios to find moles of h -2 -s -4.

01:40 And then finally, once we have moles of h -2 -s -4, we will have two variables with which we can calculate the volume.

01:51 At the end of this video, i'll show you kind of the shortcut if you can conceptually do all of these different steps.

01:58 So then we will find the volume of h2 -s -o -4.

02:08 So let's start with the first step.

02:10 Remember that when we're dealing with molarity, we're going to need liters.

02:13 So these 50 milliliters become 0 .0500 liters.

02:25 We're going to start with that as are given.

02:30 And multiply it by the malarity, which is 0 .100, moles for every one liter.

02:40 Notice that with this equation, i can have it solved for it in different ways to find what i need.

02:48 Volume is also equal to n over n, and i can also find n using molarity times volume.

02:59 That's what i'm doing here in this equation.

03:03 I find that i have 0 .00510 moles of an a .oh.

03:18 Next in our next step, we need to use multiple ratios.

03:22 And there's a secret one coefficient of brunophyte sulfuric acid.

03:26 So for every one sulfuric acid, there are two sodium hydroxide.

03:32 So essentially what i'm going to do is i'm going to divide this value by two.

03:42 So my 0 .05010 moles of sodium hydroxide are related to sulfuric acid because one mole of sulfuric acid is equivalent to 2 moles of sodium hydroxide...

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