Question
What volume of $0.296 M \mathrm{H}_{2} \mathrm{SO}_{4}$ solution would be required to neutralize completely $34.4 \mathrm{~mL}$ of $0.322 \mathrm{M} \mathrm{KOH}$ solution?
Step 1
This reaction produces potassium sulfate (K2SO4) and water (H2O). The balanced equation is: \[2 KOH + H_{2}SO_{4} \rightarrow K_{2}SO_{4} + 2 H_{2}O\] Show more…
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