00:01
Start with our balanced neutralization reaction between sulfuric acid and sodium hydroxide.
00:11
This would produce sodium sulfate and water to balance.
00:21
We need to put a two in front of the sodium hydroxide and a two in front of the water.
00:26
And in this question here, it says, what volume of 9 molar h2s .4 will react with 6 molar sodium hydroxide? and 65 .5 milliliters.
00:41
So we'll first start by calculating the moles of the sodium hydroxide, which would be equal to the molarity, times the volume converted to liters.
00:52
This would give us 0 .393 moles of sodium hydroxide, and then using our reaction stoichiometry, 0 .393 moles of sodium hydroxide, 2 moles of sodium hydroxide react with 1 mole of sulfuric acid.
01:20
This gives us 0 .197 moles of the sulfuric acid.
01:27
And then the volume of the sulfuric acid is equal to the number of moles divided by the malarity.
01:40
Give us 0 .219 liters.
01:45
This would be the volume of the h2 .s .4 that would be required...