what-volume-of-each-of-these-solutions-would-contain-5844-g-of-nacl-a-010-m-nacl-b-30-m-nacl-c-55--2

Question

What volume of each of these solutions would contain 58.44 g of NaCl?
a. 0.10 M NaCl
b. 3.0 M NaCl
c. 5.5 M NaCl

Vishal Sharma · Accepted Answer

in problem five. What volume? Off each off. The solution contained 58 point 44 g NSL. So this question is taken from the topic Preparing solution. So party is 0.10 Mueller and a C l. So as we know that the majority is basically the number off moles off salute divided by the volume off solution in later. And we know that the number off mole is equal to moss, our molecular mass. So the molecular mass off S E l is approximate 58.5 g Permal So And we find out the volume in this case or morality is, uh, equal toe number off moles. That means, uh, mass, our molecular mass in tow volume in later. So basically this formula we can use to calculate the volume. So McGarity is given in the question that is 0.10 and mass, uh, is also given. That is 58 point four and molecular masses 58.5, uh, into volume that we calculate. So on solving this we get volume and later physical toe 10 later. So, in case off the three Mueller and HCL solution is there that main polarity is three Moeller and on the same method, we can calculate its volume. So McGarity is three and this is 58.4. That is the mask our molecular masses 58.5 into volume in later. So on solving this again we get volume is 0.33 later and coming toe the party that is the 5.5 Moeller n a c l solution. So again, same method we can approach. So 5.5 physical to 58.4 upon 58.5 and two volume in later. So on solving we get volume is 0.18 later. So, uh, this these are over volume, so volume off solution one is basically 10 liter and volume off solution toe is 0.33 liters and volume of solution three is 0.18 leaders. So these are the volume. So based on data, that is 58.44 g off NSL. That when the masses given in the question and we used this formula to calculate the volume

Freddie Montague · Answer

so if this question were given the mass of the soul Ute, um, and the total mass of the solution and we have to find similarity of each solution. So we have grams of any CEO. Um, and we have volume, um, different volumes in each case. And the equation that we&#x27;re gonna use eventually to solve for the polarity is equals. Teoh C equals and Overbey, where concentration is equal to mulls over volume in concentration. It&#x27;s just another way of saying polarity, but it means the same thing. Now, if we look at what we&#x27;re given, we have volumes. But we don&#x27;t have moles. So how are we gonna be able to find the polarity? Well, luckily, were given Graham&#x27;s and using the mass in grams, we can find the moles using the molar mass. So to do that, a number of moles is equal to the mass divided by the molar mass so that we can find the moles of any seal. Now, I&#x27;m only going to do this calculation once because were given the same value for mass of any seal. So the number of moles in each case is gonna be the exact same. So moles of any CEO is equals to 3.51 grams, divided by the molar mass of any seal. And that is equal to the molar mass of sodium plus the molar mass chlorine. And those two values can be found on the periodic table. Um, and that will be equal to 22.99 grams per mole, plus 35.45 grams promote. Ah, and in total, that is equal to 58.44 grams per mole, uh, for the molar mass of any seal. So if we calculate this, we get zero point zero six 006 moves of an A seal, and that&#x27;s gonna be the same for a, B, C and D. Uh, so now that we know the moles, we can find the concentration. So for part a, the concentration is he goes to the polls that we just found 0.6 00 moles 6006 bulls divided by our bullying. Now our volume is given to us in middle leaders and we want to convert this to leaders. Since the equation C equals and over V requires the volume to be in leaders so that our units cancel out properly. Um, and we&#x27;re left. Well, in this case, we&#x27;re left with moles per leader, and that is the units for concentration. So I&#x27;m going to write 0.25 liters instead of 25 milliliters so that we have the correct units. This gives us a mill arat e of 2.40 rulers. That is the polarity of the solution. Now, for part beat, we&#x27;re going to the same thing. We&#x27;re gonna use this 0.600 moles of any CEO that I calculated for part A. So I&#x27;m not gonna do the calculation again. It&#x27;s the same because we have the same mass for our n a c l. But our William is different, so that means our concentration will be different. So you go right ahead and plug in what we have into our equation. Formal authority. That is 0.6 zero of your six moles. And again, we&#x27;re going to convert the volume from the leaders two leaders by dividing by 1000. Because there are 1000 milliliters in the leader as equal to 0.5 zero leaders, and that gives us a polarity of 1.20 molars. And this is after we round 23 significant digits per seed could do the same thing. Concentration is equal to 0.6 006 Moles began. Convert the middle leaders two leaders, 0.7 five leaders. And this gives us a similarity of 0.800 molars after we round two three significant digits. And we need three significant digits because all the values, um you are question have three significant to jets her t. I&#x27;m going to the same thing. Fromberg. Mel&#x27;s of any CEO doesn&#x27;t change here. A Boise or 600 moles and our will. He was already in leaders, so I don&#x27;t second birthday. So that&#x27;s divided by one leader, and we get a concentration cop zero points your 600 rules. But after the round, we get zero point 06 01 molars

Heather Gamble · Answer

this problem were given a number of descriptions for a query solutions of sodium chloride and water. And the question is, which two of these descriptions are absolutely identical concentration. So this 55.45 grams per litre is a pretty straightforward concentration. Uh, here we have 5.545 grams per 100 Grand&#x27;s a solution, so let&#x27;s turn that into that. Grants. Two kilograms. So we have to multiply talking bottom by 10. Because if we have 10 times as many grands sample over, but you have 10 times as many grams of talk. So we&#x27;re multiplying by 10 top and bottom, and that gives us five point 55 point or five grams in one you a gram. How solution. Now one kilogram of solution is not identical to 11 leader of solution because the density of a queer sodium chloride solution if we look it up is not identically the same as water. It&#x27;s not 1.0 grams promote. It&#x27;s actually one point zero snakes knowing grams for no so a and B are not identical. Okay, what events? E If we look at 55.45 grams in one kilogram of water. That&#x27;s not the same as one kilogram of total solution, because this would be one kilogram of water plus for a total mass. 55 point 45 grams of hcea of the sodium chloride. And so the total does not equal one kilogram. What about Dean? Well, Andy, we have milligrams per mills, but if we change milligrams to Graham, we&#x27;re going to have few World Zone. But if we scale the same down below notice, we have milligrams and milligrams. Those actually cancel. And that&#x27;s actually identically the same as 55.45 grams of sodium chloride, her 1.0 leader a solution, and then this one. We&#x27;re actually working and polarity now, and we could write that as Why times 10 to the minus three moles over by times 10 to the minus to B leaders on those would cancel it turns it. The solution is exactly one more for a major. And if you work out a polarity of one more for leader and what the concentration is based on the the molecular weight of sodium chloride and converting the mass, that doesn&#x27;t come in to 55 point for five. It doesn&#x27;t match any of them. So that guy doesn&#x27;t match. So the only two that are absolutely identical are a Andy.

David Collins · Answer

may be the hardest part of answering. This question is just the set up. So let me help you with a set up first. If this is our definition of mass percent. Graham solid over Graham solution times 100 equals R percentage. Then if we divide, will sides by percent and multiply both sides by Graham solution. We get this equation. So if I know the Graham cell you&#x27;d in the percent, I can easily calculate the Gramps solution. So if we know the masses 1.5 g of sodium chloride that&#x27;s desired, we divide it by the percent of the solution. 0.58 Multiply it by 100. That&#x27;ll be the master of the solution 2.6 kg, or 2600 g. The next 11.5 is still is desired, divided by the different percentage multiplied by 100. It&#x27;s 100 g, and then the 1.5 g of sodium chlorate is desired. From an 8.44% solution. Times 100 would get 18 g

Kim Trang Nguyen · Answer

Okay. Problem city sick when you did the problem Said they said we still see. Asked. They asked that the bottom. So what evil. Um what we re based on the city Sick day and and equal and overly so from this one will. Yet the ego and over em And similar. And he wore Well, let me see me that when any were am over model mus No, but a and more clarity whether we have I don&#x27;t someone do. Okay? And now we have an the evil and over him and we combined together. So I m we have already am to boy 14 ground. And while Aridi obsolete, Laura is a boy for a from so calm, polite this problem more clarity, boy through seven May Coppola&#x27;s people What if I they and God will ideas while we have Boy one, please. Boy, One recent leader. But they requires us todo really leader. So you have to go conversion because they re quality, you know, meaning about farming Question. Who had Alicia normally data? Okay, I do conversion here today by reading. So I 136 You need to Unless we don&#x27;t seem enough, I&#x27;ll be May way. Have I thought boy for boy 30 room. It&#x27;s a no and model mosque. Mallory Polarity of the solution equal one boy by zero And now will be ego and over him. You know, I should be the muscle at a non divide for about 30 a. M. It did not. Levi. Father, Mother must know we don&#x27;t be before we don&#x27;t. 46 old from It&#x27;s a no, All the more and probably this one. What do we have here, boy? Oh, soon. 32 Gnida, remember? Keep in mind you have tow noted the safest off this problem. Okay? They got to us if it here. So when you conversion with the milliliters, we&#x27;ve had a city jury duty. Todo both three meaning later. Can see if I see. See that boy? Oh, if I from I said that as it did, I also think passing and the money and Mollari de ego all three. Oh, you get And now we do this seeming that way you&#x27;ll be People came over and and me a boy 30 a m. Hey, man boy. 85 from and relieve I from provided by the model my mother. Most of us as a because it&#x27;s a city boy and we calculate this makeover. Matus Oh, boy. Oh, all seven do But that only Joseph it looked at the nominator only for 30 So with only specifically So we have leader on. Did you convert toe merely leader? You have type of our three Really leader, the FIFA leader. And you have 47. You done. So you have to keep this thing. I view this more formal. Okay, That&#x27;s what I got here, boy to 14. Device 58 by 45 That&#x27;s it. The more I come either that in one problem

Himanshu Garg · Answer

in this problem, we will first calculate the moles off each salute. Then we can calculate the volume in later from a polarity and the number off most off salute. Let&#x27;s do the first one Well, we have to get the volume of the solution off an easy in. We first convert the mass off initial into molds off initial by using the conversion factor from mass to move the mamas off Initial is 58.44 g and that is why this conversion factor has been used here. It gives us as 0.3662 moles off any CIA. The solution volume will be more in salute diverted by polarity, which gives us the final solution as 0.1 thing. Six liters R 1 36 family off solution. Using the similar process for each other solution, we get the 4.3 g off C two at five wet as 62.2 amel solution and 0.85 g CST. Syria It solution as 47 Emel solution

Problem

How many grams of fructose, $\mathrm{C}_{\mathrm{…

Problem 5 Easy Difficulty

What volume of each of these solutions would contain 58.44 g of NaCl?
a. 0.10 M NaCl
b. 3.0 M NaCl
c. 5.5 M NaCl

Answer

a. 10 $\mathrm{L}$
b. 0.33 $\mathrm{L}$
c. 0.18 $\mathrm{L}$

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a. 10 $\mathrm{L}$b. 0.33 $\mathrm{L}$c. 0.18 $\mathrm{L}$

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a. 10 $\mathrm{L}$
b. 0.33 $\mathrm{L}$
c. 0.18 $\mathrm{L}$

Angelica M. Stacy

Living by Chemistry