00:01
Let's calculate the volume of ethylene glycol that must be added to 20 liters of water to produce a solution that freezes at minus 10 degrees celsius.
00:12
Delta t .f.
00:13
Freezing point depression, we're told in the question, is minus 10 degrees celsius.
00:17
Let's calculate the molality, which would be minus delta tf over the kf, minus 10 degrees celsius is the freezing point depression, divided by the constant for water, which is 1 .8 .6.
00:34
Degrees celsius per moleal and we can find that the molality of the solution is 5 .4 molal.
00:43
We're told that the solution contains 20 liters of water.
00:48
So using the density of water, we can solve for the mass of h2o, which is 20 liters, or 20 .0 liters of water times the density which is one kilogram per liter which works out to 20 kilograms of water now bringing in the molality we can solve for the moles of the ethylene glycol which has a formula of we'll use the formula we'll just write it out a mole of, we'll call it f -gly, mole of ethanol, ethylene glycol...