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What was the previous far point of a patient who had laser vision correction that reduced the power of her eye by 7.00 D, producing normal distant vision for her?
0.143 $\mathrm{m}$
Physics 103
Chapter 26
Vision and Optical Instruments
Reflection and Refraction of Light
Wave Optics
Rutgers, The State University of New Jersey
University of Michigan - Ann Arbor
University of Washington
Simon Fraser University
Lectures
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In a LASIK vision correcti…
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guys in this problem. We're told to find the previous Farpoint of a patient who had laser eye surgery. Laser laser vision correction which reduced the power of a ride to seven die openers producing normal, distant vision for her key idea is normal. Dis division normal distant vision for a normal person is 50 Daio peters. So if that means after she reduced 70 eye opener, she hit 50 the orbiters. That means originally this person, Woz had a power. Her eyes had a power equivalent to 57 day openers. Another thing to keep in mind that's really important is tthe e lends to retina ratio. That distance that's not gonna change is our 2.0 centimeters. And in order to find our Farpoint a distance, we're going to use one over the I mind plus one over D not is equal to P. This is gonna be the same thing as saying. Basically, if we rearrange the variables, gonna be d not is going to be equal into the quantity of P minus one over d ies to the negative one power which is equivalent to 57 minus one over 0.2 to the negative one power. And if we write this all out, we get our answers equal to 0.143 and so are Farpoint. Distance of previous to the laser vision correction was 0.143 meters.
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