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What would be the radial (centripetal) acceleration of an astronaut standing on the inner surface of the space station, which is at a distance of 240 $\mathrm{m}$ from the axis of rotation, once the space station reaches its final angular velocity of 0.20 $\mathrm{rad} / \mathrm{s}$ ?A. 0 $\mathrm{m} / \mathrm{s}^{2}$B. 4.8 $\mathrm{m} / \mathrm{s}^{2}$$\mathrm{C}, 9.6 \mathrm{m} / \mathrm{s}^{2}$D. 48 $\mathrm{m} / \mathrm{s}^{2}$

9.6 $\mathrm{m} / \mathrm{s}^{2}$the correct answer is ${\mathrm{C}}$

Physics 101 Mechanics

Chapter 10

Dynamics of Rotational Motion

Newton's Laws of Motion

Rotation of Rigid Bodies

Equilibrium and Elasticity

University of Michigan - Ann Arbor

University of Washington

Hope College

University of Winnipeg

Lectures

02:34

In physics, a rigid body i…

02:21

In physics, rotational dyn…

02:51

An astronaut is tested in …

02:54

An astronaut is rotated in…

01:13

A rotating space station i…

01:33

What are the magnitudes of…

01:11

The formula$$N=\frac{1…

(a) What is the magnitude …

01:16

00:56

(a) Derive an equation for…

01:36

03:43

A wheel $2.00 \mathrm{m}$ …

02:19

(II) Suppose the space shu…

06:36

Whenever two Apollo astron…

02:08

As their booster rockets s…

09:53

The radius of the earth&#x…

07:06

An earth satellite moves i…

00:46

Find the centripetal accel…

03:13

$\bullet$ Consult Appendix…

01:54

$\cdot \mathrm{A}$ wheel r…

02:49

(II) In traveling to the M…

So here we know that the radio acceleration is equaling. Ah, the radius times the unknown angular velocity squared. We know the radius is equal in 240 meters and we know that. And the angular velocity equals 0.20 radiance per second. If we know both of these variables, we can simply substitute directly and say that the radio acceleration equals 240 times 0.2 squared. And this is equaling 9.6 meters per second squared. So this will be your answer. Looking at the answer choices, the correct answer is C. That is the end of the solution. Thank you for watching.

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