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When 1 mol of a gas burns at constant pressure, it produces 2418 J of heat and does 5 J of work. Determine E, H, q, and w for the process.
D) $w=\Delta E-q_{p}$$=? 7418 \mathrm{J}-(? 2418 \mathrm{J})$$\mathrm{W}=? 5000 \mathrm{J}$
Chemistry 102
Chemistry 101
Chapter 9
Thermochemistry
Thermodynamics
Chemical reactions and Stoichiometry
University of Maryland - University College
University of Toronto
Lectures
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So this problems says we're burning one mole of gas at constant pressure. Yeah, and so doing this generates two thousand four hundred eighteen jewels of heat and does five jewels of work. And so, therefore, our Q. And we want to find lt Delta H Q and W. Therefore, ACU is negative. Two thousand four hundred eighteen Jules. It's negative because we're burning this gas and it's putting off heat, so it's ah, it's losing it. And so therefore it's negative and it does five jewels of work. And so again, the work is negative. So this is our cue and W because we're a constant p. Q equals Delta H. And we can just convert this to kill a Jules and Permal. Since we have one mall of gas and then our Delta E is going to be que plus w. And so therefore we take our negative two point four one eight killer Jules Permal and we'LL convert our jewels into killer jewels for this one as well. And so doing this, we end up with negative two point four to three. Kill a Jules Permal. So that is our Delta E. This is our adult H, and then our Q and W over here
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