Composition

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right. So here way have chromium in our test tube and being a to begin is crying gas. And these tools, yet I understand heat to create a chlorine, a chromium for it and soaked Ionic Bond formation thing. Okay, so the f chromium quarrying, gas making chromium four right are unknown. But we need what we know is the mass of this compact, which is 3.45 Gramps. Okay, we can use the way out what the compound was that we created. And we can also weigh our starting chromium metal, which was one gram turn to win gases. That's why we probably couldn't even find the mass every guess. But we can now subtract what we produced from this one starting material to know how much gas was added into this top. The oldest one minus 3.45 to give two point over five grams of chlorine. So, to find the empirical formula of the final product, we need to understand how much of each Adam is present. And to understand that grams can't help us. What we need is moles. Most will give us more quantity and we know that moles is equivalent to mass sweated by moments. So then became bring our product table of elements and find the elements of each of the zones and divide mass. By that number, what we get men is 0.0 192 molds of chromium and 0.576 most of chlorine, right? So, yeah, this number is useful. However, we must have it in a interred your whole number for him. So aren't you do that until I keep this ratio, but, you know, increase it, increase the actual numbers themselves. So what we'll do, it'll do some division. We'll take this number. True. The chlorine number of moles and divided by the Korean and most simply because it's bigger is your door with you could have done that the other way wouldn't matter. I take your 0.576 over zero. Put 019 Let's see what we get. One night, two nos Uh, this equates to It's basically three right, and we know any home number. All members are over 12 3/1. So we have three chlorine atoms for everyone and there we have it. Our empirical formula, c r C l. Three

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Composition