00:01
We know the density of water is 1.
00:05
So 50 ml of water will be equivalent to 50 grams of water.
00:11
Now, we calculate the total mass of solution.
00:14
So total mass equals to 50 gram of water plus 1 .045 grams.
00:24
Total mass is 51 .45 grams.
00:29
The temperature as it increases from 25 to 32 degrees 0 .3 degrees celsius so the change in temperature will be 7 .3 degrees celsius we substitute all the known values into equation of q equals specific heat multiplied with mass of solution multiplied with change in temperature.
01:03
Substituting the values, we have 4 .18 for specific heat multiplied with total mass of 51 .045 grams multiplied with 7 .3 degrees celsius change.
01:20
The value for q turn out to be 1560 joules which is equivalent to 1 .56 kilojoules.
01:33
This this is the amount of heat absorbed by the solution.
01:39
Next part.
01:41
We have the balanced chemical equation of c .a .o.
01:45
Plus water gives out c .a .o .h .2.
01:55
In this reaction, one mole of reactant reacts with one mole of water...