Question
When 2 Amp current is passed through a tangent galvanometer. It gives a deflection of $30^{\circ} .$ For $60^{\circ}$ deflection, the current must be(a) $1 \mathrm{Amp}$(b) $2 \sqrt{3 a m p}$(c) $4 \mathrm{amp}$(d) $6 \mathrm{Amp}$
Step 1
The tangent galvanometer works on the principle of the tangent law, which states that the tangent of the angle of deflection (θ) is directly proportional to the current (I) passing through the coil. Mathematically, it can be written as: tan(θ) ∝ I Show more…
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