Question
When a $0.213-\mathrm{kg}$ mass is attached to a vertical spring, it causes the spring to stretch a distance $d$. If the mass is now displaced slightly from equilibrium, it is found to make 102 oscillations in 56.7 s. Find the stretch distance, $d$.
Step 1
Step 1: We know that the time period of oscillation is given by $T = 2\pi\sqrt{\frac{m}{k}}$, where $m$ is the mass and $k$ is the spring constant. Show more…
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When a $0.213-\mathrm{kg}$ mass is attached to a vertical spring, it causes the spring to stretch a distance $d$. If the mass is displaced from equilibrium, it makes 102 oscillations in $56.7 \mathrm{~s}$. Find the stretch distance, $d$.
When a 0.213 kg mass is attached to a vertical spring, it causes the spring to stretch a distance d. If the mass is now displaced slightly from equilibrium, it is found to make 102 oscillations in 56.7 sections. Find the stretch distance, d.
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