When a charge of 2.5 ×10^-5 C is added to a capacitor, the potential difference increases from 1

step 1 Okay, so we know the capacitance is equal to charge divided by the potential difference. We also

When a charge of 2.5 ×10^-5 C is added to a capacitor, the...

When a charge of $2.5 \times 10^{-5} \mathrm{C}$ is added to a capacitor, the potential difference increases from $12.0 \mathrm{V}$ to $14.5 \mathrm{V}$. What is the capacitance of the capacitor?

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Key Concepts

Using Incremental Changes

Calculating capacitance using incremental changes involves determining the ratio of a small added charge to the corresponding change in voltage. This method is particularly useful when the change in charge and the resulting change in potential difference are known, allowing for the evaluation of the capacitor's capacitance without needing initial absolute values.

Charge Accumulation

Charge accumulation on a capacitor involves the process where electric charge builds up on its plates when a potential difference is applied. The amount of charge stored is proportional to the capacitance and the voltage applied, according to the relation Q = CV.

Capacitance

Capacitance is a measure of a capacitor's ability to store electrical charge per unit potential difference, and it is defined by the formula C = Q/V. It quantifies how much charge a capacitor can hold for a given voltage and is measured in farads (F).

Potential Difference

Potential difference refers to the voltage across the capacitor's plates. It is the difference in electric potential that causes charge to accumulate on the plates when a capacitor is connected to a voltage source.

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