00:01
In this problem, the maximum angular magnification provided by the drop of water is 3 .5.
00:08
So to solve the part a, to find the focal length of the drop, we know at maximum magnification that m max is 1 plus 25 centimeter over f, which is for the normal i, normal near point i.
00:34
So from here we can find focal length f to be 25 centimeter over m max minus 1 and this is going to be 25 centimeter over 2 .5 and this will give me 10 centimeter which is 0 .1 meter.
01:02
Okay so to solve the part b we're going to use the lens makers equation so i'm just going to go to next page for this to solve part b.
01:17
The lens equation, lens maker's equation, is 1 over f equals n minus 1 times 1 over r1 minus 1 over r2.
01:33
So the value of n, which is refractive index here for the drop of water, is 1 .33.
01:44
And r1, we are assuming one side is flat, so r1 is going to be infinity, radius of curvature, of flat side, and r2 is what we are trying to find out.
01:59
All right...