00:01
So a rocket is launched from this point and it's going up at a rate of two meters per second.
00:13
So there is a dish or a tracking dish that is located 150 meters from the launch line.
00:21
So let's say our tracking dish is right over here.
00:24
So the distance here is 150 meters.
00:30
Okay, so we're looking for the rate of change of the angle of elevation from the distance.
00:36
A tracking dish to the rocket with respect to time.
00:41
So angle would be if we connect a tracking dish to our rocket.
00:48
So theta is this angle right over here.
00:53
And let's call this distance here y.
01:00
Then we can see that we need to write an equation that relates theta and y.
01:09
So let's write that what we have.
01:11
So we know that.
01:12
At d .y d .t is equal to two.
01:19
And what we're looking for is we want to find d theta d t at different, i guess at different distances for y.
01:35
So the first thing we're going to do before doing the different parts is let's write on the equation that relates beta and y.
01:41
So we're going to use tangent theta because we have our opposite, that is y.
01:50
And we have our adjacent because that is just a constant.
01:54
It's always 150 meters.
01:58
Okay, so this tells us that since we want d -theta d -t, we want to take the derivative with respect to t on both sides of this equation.
02:06
And if we do that, we get second squared theta times d -t is equal to 1 over 150 times d -y -d -t.
02:21
Okay, so meaning if we're we're looking for d theta d t that is just equal to uh so this is one over 150 sequin square theta which we can actually write as cosine theta since secan theta is one over cosine so this is really co squared theta over 150 times d y d t okay so now we're ready to do the different part a is we are looking for d -feta d -t just after launch.
03:04
So meaning we're looking for d -feta -d -t evaluated at y is equal to 0.
03:15
So if y is equal to 0, what is our cosine square theta? well, cosine is adjacent over hypotenics.
03:28
So if y is equal to zero, then theta is basically zero here.
03:35
Right.
03:35
So that means cost of zero is one.
03:40
Okay, so this is one over 150 times dydt, which is two.
03:46
So this is one over 75.
03:50
And our units here would be radians per second.
03:58
Now part to b, we are looking for d theta, dt, and this time we're evaluating this when the rocket is 100 meters above the ground.
04:10
So when y is equal to 100.
04:16
Okay, so then this is equal to.
04:18
So again, we're looking for cosine square theta.
04:22
So let's draw a triangle on the side.
04:26
We'll draw it right over here.
04:29
Okay, so if this is 150, this is 100.
04:34
That's our hypotenuse.
04:36
This is our theta...