Question

When a stress (which is pressure) is applied to a solid, it will deform slightly. The resulting deformation is called a strain. There are several ways of stressing a solid. In general, stresses and strains are related through an elastic modulus E, as long as we remain within the elastic limit of the solid. The general formula is: $$ E=\frac{\text { stress }}{\text { strain }} $$ The stress is always an applied pressure, and the strain is always a fractional change in some dimension, such as length or volume. If pressure P is applied equally to all sides of a solid, it changes its volume by amount $\Delta \mathrm{V}$. The pressure and resulting change in volume are related through the equation: $$ \mathrm{B}=-\frac{\mathrm{P}}{\Delta \mathrm{~V} / \mathrm{V}} $$ where V is the original volume of the solid, and B is a constant called the bulk modulus that depends on the material making up the solid. As a second example of stress and strain, consider a cylindrical wire of length L and cross-sectional area A , attached to a ceiling with one end dangling. If a force F pulls the wire downward, perpendicular to A , it will stretch the wire by an amount $\Delta \mathrm{L}$. The amount of stretch is related to the amount of applied force through: $$ \mathrm{Y}=\frac{\mathrm{F} / \mathrm{A}}{\Delta \mathrm{~L} / \mathrm{L}}, $$ where Y is called Young's modulus and is a constant that depends on material. Another important elastic modulus is called the shear modulus, S . We will not define S here; but if the solid is isotropic, $\mathrm{Y}, \mathrm{B}$, and S are related through: $$ S=\frac{Y}{2(1+\sigma)} \quad B=\frac{Y}{3(1-2 \sigma)} $$ where $\sigma$ is a dimensionless constant that depends on the material. Useful information: $$ \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2, \rho_{\text {water }}=1000 \mathrm{~kg} / \mathrm{m}^3, \mathrm{~B}_{\mathrm{Al}}=7.5 \times 10^{10} \mathrm{~Pa} $$ A $1-m^3$ block of aluminum sank to the bottom of a lake of depth 750 m . By how much did the block shrink? A. $0.1 \mathrm{~m}^3$ B. $0.01 \mathrm{~m}^3$ C. $0.001 \mathrm{~m}^3$ D. $0.0001 \mathrm{~m}^3$

   When a stress (which is pressure) is applied to a solid, it will deform slightly. The resulting deformation is called a strain. There are several ways of stressing a solid. In general, stresses and strains are related through an elastic modulus E, as long as we remain within the elastic limit of the solid. The general formula is:

$$
E=\frac{\text { stress }}{\text { strain }}
$$


The stress is always an applied pressure, and the strain is always a fractional change in some dimension, such as length or volume.

If pressure P is applied equally to all sides of a solid, it changes its volume by amount $\Delta \mathrm{V}$. The pressure and resulting change in volume are related through the equation:

$$
\mathrm{B}=-\frac{\mathrm{P}}{\Delta \mathrm{~V} / \mathrm{V}}
$$

where V is the original volume of the solid, and B is a constant called the bulk modulus that depends on the material making up the solid.
As a second example of stress and strain, consider a cylindrical wire of length L and cross-sectional area A , attached to a ceiling with one end dangling. If a force F pulls the wire downward, perpendicular to A , it will stretch the wire by an amount $\Delta \mathrm{L}$. The amount of stretch is related to the amount of applied force through:

$$
\mathrm{Y}=\frac{\mathrm{F} / \mathrm{A}}{\Delta \mathrm{~L} / \mathrm{L}},
$$

where Y is called Young's modulus and is a constant that depends on material. Another important elastic modulus is called the shear modulus, S . We will not define S here; but if the solid is isotropic, $\mathrm{Y}, \mathrm{B}$, and S are related through:

$$
S=\frac{Y}{2(1+\sigma)} \quad B=\frac{Y}{3(1-2 \sigma)}
$$

where $\sigma$ is a dimensionless constant that depends on the material.

Useful information:

$$
\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2, \rho_{\text {water }}=1000 \mathrm{~kg} / \mathrm{m}^3, \mathrm{~B}_{\mathrm{Al}}=7.5 \times 10^{10} \mathrm{~Pa}
$$

A $1-m^3$ block of aluminum sank to the bottom of a lake of depth 750 m . By how much did the block shrink?
A. $0.1 \mathrm{~m}^3$
B. $0.01 \mathrm{~m}^3$
C. $0.001 \mathrm{~m}^3$
D. $0.0001 \mathrm{~m}^3$
Show more…
MCAT: The Berkley Review Physics Book II
MCAT: The Berkley Review Physics Book II
kalbaba 1st Edition
Chapter 7, Problem 30 ↓
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When a stress (which is pressure) is applied to a solid, it will deform slightly. The resulting deformation is called a strain. There are several ways of stressing a solid. In general, stresses and strains are related through an elastic modulus E, as long as we remain within the elastic limit of the solid. The general formula is: $$ E=\frac{\text { stress }}{\text { strain }} $$ The stress is always an applied pressure, and the strain is always a fractional change in some dimension, such as length or volume. If pressure P is applied equally to all sides of a solid, it changes its volume by amount $\Delta \mathrm{V}$. The pressure and resulting change in volume are related through the equation: $$ \mathrm{B}=-\frac{\mathrm{P}}{\Delta \mathrm{~V} / \mathrm{V}} $$ where V is the original volume of the solid, and B is a constant called the bulk modulus that depends on the material making up the solid. As a second example of stress and strain, consider a cylindrical wire of length L and cross-sectional area A , attached to a ceiling with one end dangling. If a force F pulls the wire downward, perpendicular to A , it will stretch the wire by an amount $\Delta \mathrm{L}$. The amount of stretch is related to the amount of applied force through: $$ \mathrm{Y}=\frac{\mathrm{F} / \mathrm{A}}{\Delta \mathrm{~L} / \mathrm{L}}, $$ where Y is called Young's modulus and is a constant that depends on material. Another important elastic modulus is called the shear modulus, S . We will not define S here; but if the solid is isotropic, $\mathrm{Y}, \mathrm{B}$, and S are related through: $$ S=\frac{Y}{2(1+\sigma)} \quad B=\frac{Y}{3(1-2 \sigma)} $$ where $\sigma$ is a dimensionless constant that depends on the material. Useful information: $$ \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2, \rho_{\text {water }}=1000 \mathrm{~kg} / \mathrm{m}^3, \mathrm{~B}_{\mathrm{Al}}=7.5 \times 10^{10} \mathrm{~Pa} $$ A $1-m^3$ block of aluminum sank to the bottom of a lake of depth 750 m . By how much did the block shrink? A. $0.1 \mathrm{~m}^3$ B. $0.01 \mathrm{~m}^3$ C. $0.001 \mathrm{~m}^3$ D. $0.0001 \mathrm{~m}^3$
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If the volume of a block of aluminum is decreased, by the pressure (stress) on its surface is increased by (Bulk modulus of $\left.\mathrm{A} \ell=7.5 \times 10^{10} \mathrm{Nm}^{-2}\right)$ (A) $7.5 \times 10^{10}\left(\mathrm{~N} / \mathrm{m}^{2}\right)$ (B) $7.5 \times 10^{8}\left(\mathrm{~N} / \mathrm{m}^{2}\right)$ (C) $7.5 \times 10^{6}\left(\mathrm{~N} / \mathrm{m}^{2}\right)$ (D) $7.5 \times 10^{4}\left(\mathrm{~N} / \mathrm{m}^{2}\right)$

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Transcript

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00:01 In this problem we have given if the volume of a block of aluminum is decreased by 1 % that means minus delta v yv to 100 is equal to 1 so we can say minus delta v yv is equal to 0 .01 right? this is the volumetric strain right now we know that welk model is equal to a stretch and by strain so this is equal to minus delta p delta v this is the work model is so we can say this will be equal to minus delta p divided by 0 .01 so the delta p change in pressure is equal to 0 .01 to bulk modulus which is 7 .5 to 10 to the power 10.
01:08 So this is equal to 7 .5 into 10 to the power 8 newton per meter square...
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