When, after a reaction or disturbance of any kind, a nucleus is left in an excited state, it can return to its normal (ground) state by emission of a gamma-ray photon (or several photons). This process is illustrated by Equation $43.26 .$ The emitting nucleus must recoil to conserve both energy and momentum. (a) Show that the recoil energy of the nucleus is
$$E_{r}=\frac{(\Delta E)^{2}}{2 M c^{2}}$$
where $\Delta E$ is the difference in energy between the excited and ground states of a nucleus of mass $M$. (b) Calculate the recoil energy of the ${ }^{57} \mathrm{Fe}$ nucleus when it decays by gamma emission from the 14.4-keV excited state. For this calculation, take the mass to be 57 u. Suggestion: Assume $h f<<M c^{2}$.