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Problem 126 Medium Difficulty

When barium metal is heated in chlorine gas, a binary compound forms that consists of 65.95$\%$ Ba and 34.05$\%$ Cl by mass. Calculate the empirical formula of the compound.

Answer

$\mathrm{BaCl}_{2}$

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Theodore D.

Carleton College

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University of Toronto

Video Transcript

here. Similar situation is before we have our Beria metal and are test tube being heated within chlorine gas. And we produced a very ums chloride compact, unknown, Very important. Confident Even though we could guess what the compound is, we're gonna work through the math to figure out its empirical formula. And I don't mean gas. I mean, I told you, it's a very chlorate. You can figure out what it's formula. It's what we're gonna do it the long way. Okay, so we have very, um we have clarity in what we've been given is the mass percent of each at these items? And the thing about mass percent is it's a mass well, and it's the, um the race. You off the mass of each element in comparison to the mass of the whole compound. Right? So if we have ah, 100 grams of very, um, chlorate, whatever the math percent is, is what the actual masses. And that's what we're going to assume. We're not going to assume Bilic as long as we keep, um, the mass percent the same. We can choose any total mass in the multiple by the math percents of Adam Element and we can use that mass to solve this. So it's just always we have 65.95% barium, but before 0.5% chlorine. But it's safe for us to the scene. 100 grams of total product and therefore mass percent would be the same value as the actual mass. Right? So now for us to find the number of each of these Adams, we actually don't want to use mass. We want to use Moore's more, gives us that kind of information. So what we'll do is take our mass divide by more mess. Now give us nurse. So then, if we do that, we look at our product table in front moments of each of these elements. The yet a number of moles for burying to bees. Your point for eight and number of moles of chlorine to be 0.96 Is it all right? So now we can use this number to write our empirical formula. However, we need to work with intruders. So we just keep this ratio the same with the same, um ratio and turn it into, uh, introduced, if you can like, I guess we can tell that this number is double this number or pointing times. Jews double its. And if you need some convincing, we'll just simply do the division. Take 0.96 That's what we would have done anyway. Three didn't recognize, but this was 1/2 we would take and you number and divide it. But the smaller quantity of moles and then what we get is, too. And we know all whole numbers under one to over one. So then we have two chlorine atoms for everyone. Bring out. That's what that gives us, right so than our empirical formula is the A C 02 right, which is the formula's molecular formula, even for very imploring, which is what happens when you mix very imploring together. So, yes, we should have guessed this, but here's how we would have done it using math percents

McMaster University
Top Chemistry 101 Educators
TD
Theodore D.

Carleton College

Lizabeth T.

Numerade Educator

KS
Karli S.

Numerade Educator

Jake R.

University of Toronto