Question
When $\beta^{+}$ and $\beta^{-}$ particles collide, they annihilate each other, producing two $\gamma$ rays that move away from each other along a straight line. What is the approximate energies of these two $\gamma$ rays, in MeV?
Step 1
A $\beta^{+}$ particle is a positron, which is the antiparticle of an electron, and a $\beta^{-}$ particle is an electron. Show more…
Show all steps
Your feedback will help us improve your experience
Bin Chen and 71 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A positron and an electron annihilate each other upon colliding, thereby producing energy: $$-_{1}^{0} \mathrm{e}+_{+1}^{0} \mathrm{e} \longrightarrow 2_{0}^{0} \gamma$$ Assuming that both $\gamma$ rays have the same energy, calculate the wavelength of the electromagnetic radiation produced.
A positron and an electron can annihilate each other on colliding, producing energy as photons: $$-{ }_{-1} \mathrm{e}+{ }_{+} \stackrel{0}{\mathrm{e}} \longrightarrow 2_{0}^{0} \gamma$$ Assuming that both $\gamma$ rays have the same energy, calculate the wavelength of the electromagnetic radiation produced.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD