00:01
Let's talk parameters for a second.
00:04
Now, imagine you have these two equations forming your system as so, and we could use different methods to solve for x and y, being the solution to that system.
00:17
Now, let's just think about maybe like substitution.
00:21
Let's solve for y in this first equation for a second, so i can subtract 4x on both sides.
00:27
I get 2y equals negative 4x plus 8, and then i can divide by 2 across every term, and get y equals negative 2x plus 4.
00:51
So that's like something like slope interset form, i could graph it, i can see what that looks like, and then compare it to this equation on the right hand side.
01:00
And like i said, we're gonna just use substitution with our y, value here.
01:07
So i'm going to say negative 6x minus 3 times this expression, negative 2x plus 4, and simplify here.
01:23
Negative 6x, distribute that negative 3 through everything, so that becomes a positive 6x and a minus 12 equals negative 12.
01:37
It's negative 6x plus 6x.
01:40
Those cancel out, leaving us with negative 12 equals negative 12...