00:05
We have given information 6 lithium in solid state plus nitrogen in gas state 2 lithium 3 nitrogen in solid state and the mass of lithium is mass of lithium is equal to 12.
01:15
1 .3 gram and the mass of nitrogen is equal to 33 .6 gram.
01:38
The mass and the actual yield of li -3 lithium nitrate is equal to 5 .89 gram.
02:11
We have to find the theoretical yield of li3 and the percent yield.
02:51
So first we have to find the limiting reactant.
03:23
The number of moles of lithium is number of mores of lithium is equal to mass of lithium divided by molar mass of lithium is equal to by putting the mass values 12 .3 gram per mole is the given mass of lithium and 6 .941 gram per mole is the molar mass of lithium is equal to 1 .8 mole.
04:33
Gram gram oh sorry here is only mole because here we we have put the value of oh sorry mass of lithium so mass of lithium the unit of mass of lithium is gram so here we can sell gram gram so mole is left here so the unit of number of moles is equal to member of moles of is equal to 1 .8 mole of lithium and the number of moles of nitrogen is number of of nitrogen is equal to given mass of nitrogen divided by molar mass of nitrogen is equal to given mass of nitrogen is 33 .6.
06:09
Gram and molar mass of nitrogen is 28 .014 gram per mole.
06:20
Here you can sell gram gram and the value is 1 .2 mole with the calculated value and 6 moles of lithium reacts with 1 .3 mole of of nitrogen therefore 1 .8 moles of lithium will react with 1 .8 divided by 6 is equal to 0 .3 moles of nitrogen since there is access so the limiting reactant is lithium.
08:42
Now we will calculate the theoretical yield of lithium nitrate.
09:17
And 6 moles of lithium produce 2 moles of light 3 in...