00:04
In this question, we have hydrochloric acid reacting with potassium sulfide, and we're told that 42 .9 millimeters of hydrogen sulfide gas is produced at 752 tor and 258 degrees celsius.
00:19
And we're asked to write an equation for the gas evolution reaction and then determine how much potassium sulfide in grams reacted.
00:26
So the equation, we had hydrochloric acid, so hcl, reacting with potassium sulfide.
00:35
So k2s, and that is forming hydrogen sulfide gas, and it's also going to form kcl.
00:47
So then if we balance this equation, we're going to need two hcls to account for these two hydrogens, which means that we need two kcls.
00:56
So there's our balanced equation, and then we're going to figure out how much potassium sulfide in grams reacted to form this much hydrogen sulfate.
01:06
Sulfide gas.
01:08
So the first thing i'm going to do is find out how many moles of hydrogen sulfide gas are in this quantity that we're given.
01:15
And to do that, i need all of my units to be correct to use in the ideal gas equation.
01:21
So my volume needs to be in liters.
01:22
So to get to liters, i will divide by 1 ,000 and i'll have 0 .0429 liters.
01:29
My pressure needs to be in atmospheres.
01:31
To get from toward atmospheres, i'll divide by 760.
01:34
So i have 1 .02.
01:37
Atmospheres and my temperature needs to be in kelvin...