Question
When methyl bromide is dissolved in ethanol, no reaction occurs at $25^{\circ} \mathrm{C}$. When excess sodium ethoxide is added, a good yield of ethyl methyl ether is obtained. Explain.
Step 1
Sodium ethoxide is a strong base and it reacts with ethanol to form ethoxide ion and sodium ion. This can be represented as follows: \[ \text{CH}_3\text{CH}_2\text{OH} + \text{Na} \rightarrow \text{CH}_3\text{CH}_2\text{O}^- + \text{Na}^+ \] Show more…
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