00:01
For this problem, it states that we have nitrogen dioxide and the nitrogen dioxide is going to react with water, producing nitric acid and it says nitrogen oxide.
00:16
So it wasn't specific, but i assume they meant nitrogen monoxide.
00:22
So we'll put nitrogen monoxide right here.
00:25
Then we see that we have two hydrogens and only one hydrogen, so we need to put that two right there.
00:30
Then we have two nitrogen plus another nitrogen there, so three nitrogen, so we need to put a three right there.
00:39
Now the chemical equation is balanced.
00:43
It then asks how many moles of each product can be produced from 0 .250 moles of water.
00:50
So we're going to start with 0 .250 moles of water and assume that we have sufficient nitrogen dioxide, although not explicit in the problem, and figure out how much, how many moles, of nitric acid we can make from 0 .25 moles of water and then in a subsequent calculation how many moles of no we can make with 0 .25 moles of water.
01:14
We see that the relationship between moles of water and moles nitric acid is 2 to 1.
01:23
So for every mole water we'll make 2 moles nitric acid so we'll make twice the amount .5 .00 moles nitric acid.
01:31
Then the multiple relation for water to nitrogen monoxide is one to one.
01:38
So we will end up with the same number of moles of nitrogen monoxide as reacted of water.
01:47
Then for the next question, it asks how many grams of nitric acid can be produced from a particular mass of nitrogen dioxide.
01:57
That mass is 60 .0 grams nitrogen dioxide.
02:01
So this is going to require us to go from grams of nitrogen dioxide...