00:01
To determine the order of the reaction and the rate law and everything else that we need to solve for this question, we need to plot the data provided.
00:10
We'll take the time in minutes and the corresponding concentration, and we'll plot concentration as a function of time.
00:19
If we get a straight line as represented by an r -squared value of at least 0 .99, with the plot of concentration as a function of time, it would be zero order.
00:30
Overall, if we get a straight line with the natural log of the concentration as a function of time, then it would be first order, which we don't.
00:43
If we get a straight line, .998, which we do here, when plotting one over the concentration as a function of time, then it's second order, and the slope is equal to the rate constant.
00:56
So what i had to do is i had to take the concentration, take the natural log of the concentration, and then calculate one over the concentration so that i could prepare all three of these graphs.
01:10
So what is the rate law? well, the rate law is going to be rate is equal to k multiplied by the reactant concentration squared, or it could be k multiplied by phenyl acetate raised to the one, no, we're not doing enelacitate.
01:46
We're doing phenyloid bromide.
01:51
It'll be phenyloid raised to the one.
01:59
And then pirating raised to the one.
02:04
The overall order is second, but each one is going to be individually first order...