When riding in a 1300-kg car, you go around a curve of radius 59 m with a speed of 16 m / s. T

step 1 A car with the mass of 1 ,300 kilograms is going around a curve, which has a radius of 59 meters

When riding in a 1300-kg car, you go around a curve of...

When riding in a $1300-\mathrm{kg}$ car, you go around a curve of radius $59 \mathrm{~m}$ with a speed of $16 \mathrm{~m} / \mathrm{s}$. The coefficient of static friction between the car and the road is $0.88$. Assuming that the car doesn't skid, what is the force exerted on it by static friction?

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Key Concepts

Static Friction

Static friction is the force that prevents two surfaces from sliding past each other. In the context of circular motion, it can act as the provider of the necessary centripetal force to maintain the motion. Its maximum potential value is given by the product of the coefficient of static friction and the normal force, ensuring that the object remains in its circular path without skidding.

Newton's Second Law of Motion

Newton's Second Law states that the net force acting on an object is equal to the mass of the object multiplied by its acceleration (F_net = m*a). In problems involving circular motion, this law is central in linking the centripetal acceleration (v²/r) of the object to the forces acting on it, such as static friction.

Centripetal Force

This is the net inward force required to keep an object moving in a circular path. It is calculated using the formula F = m*v²/r, where m is the mass, v is the speed, and r is the radius of the circular path. This concept explains why an object traveling in a circle must constantly change direction, requiring a constant inward force.

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