When the effect of aerodynamic drag is included, the $y$ -acceleration of a baseball moving vertically upward is $a_{u}=-g-k v^{2},$ while the acceleration when the ball is moving downward is $a_{d}=-g+k v^{2},$ where $k$ is a positive constant and $v$ is the speed in meters per second. If the ball is thrown upward at $30 \mathrm{m} / \mathrm{s}$ from essentially ground level, compute its maximum height $h$ and its speed $v_{f}$ upon impact with the ground. Take $k$ to be $0.006 \mathrm{m}^{-1}$ and assume that $g$ is constant.