00:01
Okay, so in this problem, we are looking for the pressure of a tire when it heats up to 40 degrees.
00:09
So let's get down the givens and we can discuss how to do the problem.
00:12
So it's final temperature, it's 40 degrees c, and i want to immediately convert this to kelvin if i'm going to use the ideal gas law.
00:21
I think it's generally a bad idea to use celsius in the ideal gas law because the relationship between these is additive.
00:27
So you're never going to do any unit cancellations like you would be if it were multiplicative.
00:33
And if that's hard to understand, i mean, just try to just do a problem with celsius and see how it goes wrong.
00:41
Or maybe it won't.
00:43
Maybe there's something i'm missing, but some edge case.
00:47
But anyway, so, okay, so 273 plus 40 is 313 kelvin.
00:59
And the initial temperature is 20 degrees celsius.
01:08
And so again, let's convert that to kelvin.
01:12
So then we get 293 kelvin.
01:17
I think if you're doing temperature differences, it's okay to not convert.
01:20
I think that was the case that i had in the back of my mind.
01:23
Okay.
01:25
And psi, the pressure is 32 psi.
01:28
Here, p initial 32 psi.
01:33
And then our goal is to get, i think, the pressure, the final pressure.
01:48
So let's use the ideal gas law.
01:50
We know for the error in there, pv is equal to nrt.
01:58
And let's say if r and t and n stay the same, we know from initial to final, that p initial, v initial, is equal to p final.
02:09
V -final.
02:11
And then let's point out, too, i think that these p's are gauge pressure.
02:14
So that means that the total, and we want to use absolute pressure here.
02:22
So actually the absolute pressure, sort of like we did with temperature, we need to add the 14 psi from the atmosphere.
02:32
Because, i mean, air already produces, you know, produces pressure.
02:38
And so this is the additional pressure you need or else the tire would be.
02:41
Be deflated.
02:43
So then the initial total pressure is actually 46 psi...