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When two cotton plugs, one moistened with ammonia and the other with hydrochloric acid, are simultaneously inserted into opposite ends of a glass tube that is 87.0 cm long, a white ring of $\mathrm{NH}_{4} \mathrm{Cl}$ forms where gaseous $\mathrm{NH}_{3}$ and gaseous HCl first come into contact $\mathrm{NH}_{3}(g)+\mathrm{HCl}(g) \longrightarrow \mathrm{NH}_{4} \mathrm{Cl}(s)$ At approximately what distance from the ammonia moistened plug does this occur? (Hint: Calculate the rates of diffusion for both $\mathrm{NH}_{3}$ and $\mathrm{HCl}$ and find outhow much faster $\mathrm{NH}_{3}$ diffuses than HCl.)
51.71 $\mathrm{cm}$
01:57
Aadit S.
Chemistry 101
Chapter 9
Gases
University of Central Florida
Rice University
University of Kentucky
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So in this podcast we're looking at diffusion again. So we just jumped to another podcast. We can see another right of diffusion of a is personal to one over m A. On the rate of diffusion of a divided by the rape. Diffusion of B is equal to the root of ambi over m A where Amnesty molecular weight. So we'll jump in, for example, here. So the right of diffusion Bob and H three, divided by rate of diffusion of H C l is equal to root um hcl divided by route, um at age three. So that is equal to route 36.5. Bye Bye. Route 17 g pommel equals 1.465 So the diffusion rate of NH three is 1.465 times faster than HCL. So therefore, the distance covered by NH three will be 1.465 times greater than HCL, so the length of the glass tube is 87 point. There were centimeters let the distance covered by HCL B X, so distance hcl and at age three, distance equal to the length off the glass tube. So what we have is X at 1.45 x people to 87. So we saw X. That is 35.29 centimeters. And so the distance covered by HCL 35 went to nine centimeters. Distance covered by an H three is 51.71 centimeters. Therefore, the white ring of an H for Seattle is formed to 51.7 months, centimeters away from NH three, Yeah.
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