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When we burn 10.00 g of phosphorus in O2(g) to form P4O10(s), we generate enough heat to raise the temperature of 2950 g of water from 18.0 C to 38.0 C. Calculate the enthalpy of formation of P4O10(s) under these conditions.

$$3057.530 \mathrm{kJ} / \mathrm{mol}$$

Chemistry 102

Chemistry 101

Chapter 9

Thermochemistry

Thermodynamics

Chemical reactions and Stoichiometry

Carleton College

University of Central Florida

Rice University

Lectures

00:42

In thermodynamics, the zer…

01:47

A spontaneous process is o…

01:11

When we burn 10.00 g of ph…

05:46

When 10.00 g of phosphorus…

02:49

Apply Phosphorus trichlori…

01:33

Elemental phosphorus burns…

01:16

When 5.00 g of a compound …

04:32

When $1.645 \mathrm{g}$ of…

01:41

Burning $1.43 \mathrm{g}$ …

03:10

The enthalpy of combustion…

05:29

Suppose you burned 0.300 g…

12:12

Phosphorus (P. ) is commer…

03:19

Sulfur $(2.56 \mathrm{g})$…

02:06

The enthalpy change for th…

01:52

06:26

Use standard enthalpies of…

07:10

Calculate the enthalpy of …

White phosphorus is prepar…

03:50

When 1.045 g of CaO is add…

04:14

The complete combustion of…

02:41

The standard enthalpy of f…

03:39

How much heat is required …

So this problem tells us we're burning ten grams of phosphorus p for ah in oh, two to form P for Oh, ten solid. And so we're gonna call this p four since we have a P for over here. So the equation is balanced, and the first thing we can do is find the heat. Since we're told that this is enough heat Ah, for a certain mass of water to change a certain temperature, we confined the amount of heat that is. And so we have our massive water. Twenty nine fifty grams times are specific heat of water four point one eight four Jules per gram degrees Celsius. And then our delta T is thirty eight point zero degree Celcius minus eighteen point zero degrees Celsius. And so that gives us a heat of two, four, six, eight, five, six Jules or two four, six point eight five, six. Kill it, Jules. And now Ah, we know that this is an extra thermic reaction, so we know our heat is going to be a negative value, and that is just a sign convention. And so now that we have our heat and kill a Jules, we confined our amount of moles in order to determine our final answer. And so we have ten grams of P for we want to divide that by the Moler massive p for one twenty three point nine zero grams per mole. And since we want P for oh, ten, we just take one mall of P four is one mall of P for oh ten, since that is our one to one ratio. And then we get our final answer in moles of P for oh ten, which is equal to zero point zero eight zero seven moles of P for Oh ten. And so now we just take our negative two forty six x point eight five six Killa jewels and divided by our zero point zero eight zero seven moles on We get our final answer to be negative three thousand zero fifty eight point five. Kill a Jules Permal, and that is our final answer.

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