Question
When $y<\frac{1}{2} x^{2}, y^{\prime}=x^{2}-2 y$ is positive and the portions of solution curves "outside" the nullcline parabola are increasing. When $y>\frac{1}{2} x^{2}$ $y^{\prime}=x^{2}-2 y$ is negative and the portions of the solution curves "inside" the nullcline parabola are decreasing.
Step 1
First, we are given the inequality $y < \frac{1}{2}x^2$. This means that the value of $y$ is less than half of the square of $x$. In other words, the graph of $y$ lies below the parabola $y = \frac{1}{2}x^2$. Show more…
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