Question
When you move up from the surface of the earth, the gravitation is reduced as $g=9.807-3.32 \times$ $10^{-6} z,$ with $z$ as the elevation in meters. By how many percent is the weight of an airplane reduced when it cruises at $11000 \mathrm{m} ?$
Step 1
We can do this by substituting $z = 11000$ into the given equation $g = 9.807 - 3.32 \times 10^{-6} z$. This gives us: \[g = 9.807 - 3.32 \times 10^{-6} \times 11000 = 9.7705 \, \text{m/s}^2\] Show more…
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When you move up from the surface of the earth, the gravitation is reduced as $g=9.807-3.32 \times$ $10^{-6} z,$ with $z$ being the elevation in meters. By what percentage is the weight of an airplane reduced when it cruises at $11000 \mathrm{~m} ?$
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at what distance above the earth's surface will your weight decrease to half of what it is at the surface the radius of the earth is 6.38 x 10^6 m
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