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.. Where must you place an object in front of a concave mir-ror with radius $R$ so that the image is erect and 2$\frac{1}{2}$ times thesize of the object? Where is the image?

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$\begin{aligned} s &=0.3 R \rightarrow \text { the object } \\ s^{\prime}=-2.5 s &=-2.5 \times-0.75 R \rightarrow \text { the image } \end{aligned}$

Physics 102 Electricity and Magnetism

Physics 103

Chapter 24

Geometric Optics

Electromagnetic Waves

Reflection and Refraction of Light

University of Michigan - Ann Arbor

Hope College

University of Sheffield

Lectures

02:30

In optics, ray optics is a geometric optics method that uses ray tracing to model the propagation of light through an optical system. As in all geometric optics methods, the ray optics model assumes that light travels in straight lines and that the index of refraction of the optical material remains constant throughout the system.

10:00

In optics, reflection is the change in direction of a wavefront at an interface between two different media so that the wavefront returns into the medium from which it originated. Common examples include the reflection of light, sound and water waves. The law of reflection says that for specular reflection the angle at which the wave is incident on the surface equals the angle at which it is reflected. Reflection may also be referred to as "mirror image" or "specular reflection". Refraction is the change in direction of a wave due to a change in its speed. The refractive index of a material is a measure of its ability to change the direction of a wave. A material with a higher refractive index will change the direction of a wave to a greater degree than a material with a lower refractive index. When a wave crosses the boundary between two materials with different refractive indices, part of the wave is refracted; that is, it changes direction. The ratio of the speeds of propagation of the two waves determines the angle of refraction, which is the angle between the direction of the incident and the refractive rays.

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Where must you place an ob…

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A concave mirror forms a r…

All right. So for an image that is erect, m will be greater than zero. We're in direct image on DH. So the magnification here is therefore plus 2.5. We know that that is equal to negative image. Distance over object distance. So this implies that image distances link 2.5 times object distance. Okay, um and so so we use this formula for focal length. One focal length is actually two over. Artist, remember, struggling just to start over too. On that's equal to one arrest plus one arrest prime. And so that is a cool team. One of us minus one over tutoring five s. You can re concerns this equation to get s equals point 30 R on that, that implies that it's prime is negative. 2.5 times point. These are are so as prime his negative 0.75 are on DH. That's it. The object is should be point. Many times, the times, the radius of curvature, distance away and image should be 0.75 times are in the opposite. In the other direction that burned in their direction from the lens

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