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Which ion with a +1 charge has the electron confi…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84 Problem 85 Problem 86

Problem 56 Easy Difficulty

Which atom has the electron configuration 1$s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{7} 4 s^{2} ?$

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Chemistry 101

Chemistry

Chapter 6

Electronic Structure and Periodic Properties of Elements

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Video Transcript

So this problem, we're giving it an electron configuration, and we just need to determine which which element in the periodic table corresponds to this particular electron configuration. So we just have the periodic table in front of us. We can very easily walk along the different blocks to make up this table to figure out which Adam this is so we see that it has a fulfilled one s orbital. So we passed hydrogen and helium fully filled two s orbital. We're gonna move path, licit lithium and brilliant, fully filled to pee. Fully filled. Three s fully sold, three p. We see that it has two electrons in the four s, which means because it doesn't have 10 electrons and it's three d block. We know that we're looking at an element within this first period of this This D block here. So we know that again we have There's two electrons in the four s. We start at Skinny. Um, we just walk seven electrons over. So scanning has one electron in its three d 234 by 67 and we end at quibble. So that means kobo is the element represented by this electron configuration.

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