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So in this video we're going to talk about question 60 from chapter 8, which asks us which compound in each of the following pairs of ionic substances has the most exothermic lattice energy.
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Justify your answers.
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So the lattice energy is equal to a proportionality constant that corresponds to the arrangement of the solid times the charge of one of our ions times the charge of our other ion divided by the, distance between those charges.
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So if we have larger charges like minus two and plus two instead of minus one and plus one, then our lattice energy will be larger.
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It'll be more exothermic.
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And if we have smaller distances between them, our lattice energy will be larger.
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So as atomic radius increases, lattice energy decreases.
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So in a, we have lithium fluoride and cesium fluoride.
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So the difference is lithium and cesium.
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So let's look at a periodic table.
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So lithium is here.
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It's one of our alkali metals and cesium is also an alkali metal, but it's way down here.
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So cesium has a much larger atomic radius than lithium.
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Just to refresh ourselves on the trends in atomic radius as we go down the periodic table and we add more shells of electrons, we are increasing our atomic radius.
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Whereas if we go from left to right across the periodic table, we're increasing the number of protons, which are going to have a tighter pull on those outer electrons.
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So we're actually decreasing atomic radius from left to right.
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But in this case, we're comparing the atomic radius of lithium to the atomic radius of cesium because we know they're both going to have the same charge.
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So the only difference is size.
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And cesium is much larger than lithium.
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So, so we said that as atomic radius increases, lattice energy decreases.
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So the smaller atom, lithium, is going to be the one with the more exothermic lattice energy.
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So a is lithium fluoride.
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Then we have sodium bromide and sodium iodide...