00:01
Hello everyone, let us see the following question.
00:02
In which reaction no product is obtained? no product.
00:08
So let us see the reaction one by one.
00:11
So reaction a is ominia paraplaced nitro when treated with ch3 ona.
00:23
See, we know that nucleophilic substitution is not possible.
00:27
As we know, phenylic carbocation cannot be formed due to resonance stabilization, but it is, is possible in the presence of electron withdrawing group.
00:36
So bromine is replaced with a new nucleophile och3.
00:41
Therefore the product obtained in this case should be due to the presence of nitro growth nucleophilic substitution happens.
00:50
So product is obtained.
00:53
So let's see question b where once again i am having sodium phenoxide and a nitro group.
01:00
As i told you in the presence of a nitrogroup, nucleophilic substitution is favored.
01:06
So once again the product here would be br and nitro group as it is ch3 one...