which-has-more-particles-a-balloon-filled-with-10-l-of-oxygen-mathrmo_2-gas-or-a-balloon-filled-with

Question

Which has more particles: a balloon filled with 10 L of oxygen, $\mathrm{O}_{2},$ gas, or a balloon
filled with 15 L of hydrogen, $\mathrm{H}_{2},$ gas? Explain your reasoning. Assume STP.

David Collins · Accepted Answer

question Number six goes back to of a God rose law and also takes into account the number of moles of gas that are present at STP. To determine the number of moles of gas that are present at STP. Standard temperature and pressure. We need to relate the volume to the number of moles. We know that at STP, any gas has a volume of 22.4 leaders if we have one mole. So there&#x27;s this direct relationship at STP between the moles of the gas and the volume of the gas. So if we have 15 leaders of H two gas at STP and 10 liters of 02 gas at STP, the one that has the greater volume, it will be the one that has the mortgage gas particles in this case gas molecules 02 molecules or H two molecules. The answer for this one will be. The 15 liters of hydrogen has mawr gas particles than 10 liters of oxygen

Ronald Prasad · Answer

if we have two balloons filled with um air and the other with helium seem pressure, volume and temperature. So when pressure volume in temperature are the scene, the number of moles in an ideal gas is independent of the gas itself. Therefore, both balloons, uh, the one with air and the one with helium contain. You seem number of particles, and when we talk about particles, these could be Adams and molecules. They would be identical irrespective of the gas it&#x27;s filled with.

Jason Boomer · Answer

this question asks us which of three samples contains the most molecules 1.0 liters of 02 NSTP 1.0 leaders of Herod, STP or H two at STP and right off the bat, I&#x27;m going to tell you that this is a trick question. They&#x27;re all the same. And now we&#x27;re gonna talk about why So the math behind this, we&#x27;re thinking about it mathematically, we&#x27;re going to use their ideal gas law. TV is equal to NRT and what we&#x27;re trying to find is the number of molecules which is proportional to the number of moles, right? It&#x27;s the number of most times Avago address number. So if we can prove that they all the same number of moles, then that&#x27;s enough to prove the veil of the same number of molecules as well. So let&#x27;s go ahead and rearrange this so that we have end by itself by dividing both sides by rt. So we have pressure times volume divided by the gas constant or in times temperature is equal to the number of moles. And if we look at what that would be for oxygen, so the pressure we know because that s t P, that the pressure is one atmosphere. The volume is given as one leader. The constant is going to be 0.8 to 1, and the temperature is also it STP so that zero Celsius or to 73 Kelvin Now you&#x27;ll notice at no point in that Did I discuss that it is 02 There is none of those variables that is Onley true for 02 The pressure, all three of them are at the same pressure. So if the pressure is equal, it&#x27;s put it in red To indicate that that&#x27;s not changing, the pressure is equal for all three of them, so that isn&#x27;t going to change our answer. The volume is one point a leader for all of them one point oo leader. So the volume is not changing for any of them either. So that&#x27;s not going to affect our answer. The constant will. It&#x27;s a constant Constance don&#x27;t change so that one&#x27;s not going to affect anything and the temperature at STP again they all have the exact same temperature. So we&#x27;re gonna be doing the exact same calculation three times if we want to figure out which one of these has the most number of molecules, and I&#x27;m not going to bother doing that math because I know that if it&#x27;s the exact same calculation, it&#x27;s gonna give us the exact same number every time. So this is why all three of these have the same number of molecules.

Sara Ross · Answer

eventually asking us to find the density of gaseous hydrogen, 25 degrees Celsius and one atmosphere of pressure. And then compare that to the density of dry air, which is given to us as 1.185 times 10 to the negative three grams per centimeters. Cute. So this is a pretty textbook ideal gasela situation. So we&#x27;re gonna go ahead and just write down the Gasela and then since n, which is the number of moles isn&#x27;t given in this equation, will rewrite this as a more usable form for us, where n is given as grams, divided by the Mueller mass of a substance Times R t Now to solve for the density of hydrogen that&#x27;s going to be given in the form of grams over volume. And so to rewrite that in terms of the ideal gas law, G over V is going to be equal to the pressure times the molar mass divided by R T. And we can actually go ahead and just plug in there our plug in each of these values to solve for what that density is equal to. So the P is given us one atmosphere. Moller Massieu console from the periodic table is equal to 2.0 16 grams per mole. And that&#x27;s gonna be divided by our universal gas constant, which is 0.8206 Technically, leaders times atmospheres over k times moles, but that&#x27;s a lot too right. But if your professor is picky about units, make sure to write that Times 298 Kelvin, which is going to give you a density of 0.0. It&#x27;s 24 grams for leader. Nice, however, note that we&#x27;re comparing it to units of grams over centimeters cubed, and we currently have it written as grams over leaders. So to convert that scroll down a little bit through for school down, maybe way too far. There we go. Oh, no figuring out the scroll thing. OK, One leader is equal to 1000 milliliters, which is the same as one 1000 centimeters. Cute. So if we take the density of hydrogen, which is equal to 0.0, it&#x27;s 24 grams for leader or per 1000 centimetres cubed, we get a density that is 8.24 times 10 to the negative five grams per centimeter cubed. Excellent. So now we have to just compare that through the density of dry air, which is equal to one 0.1 it five times 10. So the negative three grams per si m squared. And using this ratio, you&#x27;ll get something to the effect off one over 14.4. Which means that dry air, which is this&#x27;ll value right here. And that value right there we just calculated was hydrogen air is 14.4 times more dense, then hydrogen. So there is the answer to your second part, and that is the answer to the first part of the question.

Kevin Zaborsky · Answer

in this question were given to different partial pressure values for nitrogen gas and oxygen gas in a mixture between the two. We want to determine which one of these two molecules that is molecules of 02 or into experience more collisions. Recall that one of our definitions for pressure is the force that gas particles exert on the inner walls of a given volume. As his gas particles exerted greater force on the walls, they move around with a greater speed, and because of that, their frequency of colliding with one another increases. And so that is directly proportional to the pressure that those particles exert on the wall. So we would expect molecules with a higher pressure to be experiencing more collisions. And when we compare these two, we see that since the partial pressure of oxygen is higher than for nitrogen, that the oxygen 02 molecules experience more collisions than the nitrogen molecules again because they exert a greater pressure in the mixture of gas, they have lorded your partial pressure between the two of those molecules

David Alvarez-Carbonell · Answer

okay. In this problem, we have two samples. One Ophelia on day one off hydrogen in the sample of helium. The information we have is that, um be the size off the balloon, which is a container in which the gas is. He&#x27;s half the size of the balloon off hide. Really? In other works, we have that the size. Well, the hydrogen balloon. He&#x27;s twice the size of the hill. You mug, We we can&#x27;t right away. Convert those words to into in terms of the kilometers off. The idea got because we know we will be working with ideal gas concept. An equation. So they volume off the hydrogen volume. He&#x27;s twice this size, the volume off the helium. Okay, Or we do it on the side. We say that the volume off Killian? Yes. Huh? Volume. Private gym. What is that we have we have about the pressure off gas in the hydrogen balloon. These one atmosphere, whereas the pressure off the helium in the helium balloon is to atmosphere the hydrogen balloon. He said a temperature off negative five. We know we have to convert these quickly to killed me so that we can use it in the killed in the ideal gas equation. That would be five Celsius, plus not negative. Faisal&#x27;s just close to 73. That&#x27;s to 68 killed in the temperature for the helium sample. He&#x27;s 23 degree sells years, and she said we wanted to 296. Gold is okay. We have to first determine which of the two volume contains the greater number of molecules. In other words, we need to determine and in each of this samples and is a number of moulds, which is directly proportional to the number off molecules. In order to that we&#x27;re going to use, they deal. Goss equation the product of the pressure on the ability of people&#x27;s the number of moles, times the constant They deal, Gus, that we were not use the one that contains atmosphere Penis units. Darwin is 0.8 to leaders atmosphere, moles to the negative one buildings to the negative one. Okay, um, let me fix this here one second. No. So then it takes one into any good Okay times, so p times B equals end times are times t that them for sure. For the case off eso because we have to find in We need to solve for n and equals creamy do you body by rt In the case off helium, Aunt Ophelia is the pressure of helium times the volume of helium which is have the volume off hydrogen divided by all right on the temperature Ophelia The number of moles of hydrogen is the pressure of hydrogen times the volume of hydrogen divided by R on the temperature off hydrogen. The number of more Ophelia is therefore to atmosphere. But when I started substituting toe atmosphere, we don&#x27;t know the volume. So we will keep working with have volume, work hydrogen anybody by a r which is 0.82 leaders atmosphere most negative one Give me one times the temperature of feeling which is 296 Kelvin. The number of months off hydrogen is the pressure of hydrogen. Just what atmosphere times the volume of fighter year, which we don&#x27;t know. Divided by R 0.82 leaders atmosphere most negative one curving negative one times temperature and killed in which is to 68 killed A okay, so in both cases killed him to the negative one cancer with calving getting into the makeup if one concert with building, uh, atmosphere council with atmosphere, atmosphere, concept with atmosphere. We know that the leaders will cancel anyways because, um, these volume isn&#x27;t leader this volume missing leader. So we are left with multiple. And I got one. Yeah, here in the denominator. Which means that there would be more in the numerator. What about? That&#x27;s what we&#x27;re looking before. So Ah, we sold for these later calculations here. The number of moles of helium, these they still gone this to be stood toe are cancelled. And then we divide one divided by 0.82 divided by 2 96 and we get 0.40 point zero for one toe. See your point 0412 uh, times the volume hydrogen when we sold for age for hydrogen. When we get these one divided by to your 0.82 do you body by to 68 and we get zero point 04 by five volume off hydrogen. Okay, now we don&#x27;t need to know the volume of hydrogen because all we need to goto answer a east to compare, then to compare the number of balls on if we assume on if this number is the same the volume of hydrogen, say one leader, then obviously we&#x27;re going to have more Morse off Heidi, and therefore we&#x27;re gonna have more malls. Are a more *** off? Five years. So these answer questions a then the number of most of hydrogen is greater than the number of more off here under four. The number of molecules. Okay, no toe answer. Be in B. We need toe. Determine which of the two has a greater must of guys. For that, we convert this number of moles to grants. Okay, so in the case of helium, it would be zero point zero for 12 most or times volume off hiding most divided by the molar mass off helium. The more my mask off heal you. He&#x27;s four four grams herbal. Sorry, we won&#x27;t apply. We want to play. So the number of mostly multiply by the mortar mass for in the case of feeling grants for more molds will cancel. And then we are left with you know point, you know, for 12 times for that zero point 16 five grams times volume of five. Okay, grants, aunt. Here we have zero point for indicates of fighting. We have 0.455 times by William off hydrogen moles times the more mass of hydrogen. Jace. Two times one. That weight of hydrogen. Yeah, to grounds per mole. Most will cancel. And then we have syrup 0.4 by five times to that 0.9 grounds Giants. They look so actually, I like to put it the right way. The number is the number is in the case of feelings, your 0.165 time the volume off hydrogen that we don&#x27;t know that we don&#x27;t need grants. And then these only 0.91 boarding height again grounds. Okay again. Because we know that a volume is the same. Assume one leader. This is a greater must. The mask off feel you on that will answer question. Be there must off helium. He&#x27;s created that they must

Problem

At $25^{\circ} \mathrm{C}$ which balloon has the …

Problem 6 Easy Difficulty

Which has more particles: a balloon filled with 10 L of oxygen, $\mathrm{O}_{2},$ gas, or a balloon
filled with 15 L of hydrogen, $\mathrm{H}_{2},$ gas? Explain your reasoning. Assume STP.

Answer

H2 sample

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