00:01
So in this video we're going to work through question 6 from chapter 8 which asks us which has the greater bond length and no 2 minus or in 03 minus explain.
00:09
So let's go ahead and draw the lewish structures for in 02 minus and then do a little comparison of them.
00:17
So we know that nitrogen is going to bring five valence electrons and each of our two oxygen atoms will bring six valence electrons and then we have a minus one charge so we're going to have one extra electrons so we have a total of 18 valence electrons to work with when we're drawing our lewish structure.
00:35
Let's go ahead and put our nitrogen atom as our central atom and then we have our two oxygen atoms.
00:42
So one possibility that we could do would be to singly bond each oxygen atom to my central nitrogen atom and then fill in the octets.
00:56
So when i do that, i actually have two electrons left over.
01:02
Remember i have 18 valence electrons total and i've only used 16, so i'm going to put those two extra electrons on my central nitrogen atom.
01:09
So is this a good lewis structure? how do we know? well, we can look at the formal charges on each atom.
01:15
So the formal charge is equal to the number of valence electrons minus the number of electrons in lone pairs around the atom, minus half of the number of electrons in bonds that that atom is making.
01:26
So in oxygen, we have six minus six minus one.
01:31
That gives us a formal charge of minus one on both of our oxygen atoms.
01:35
And then what about our central nitrogen atom? we have five valence electrons minus two, minus two in bonds.
01:42
So that gives us a formal charge of plus one.
01:44
So we have formal charges of minus one, plus one, and minus one.
01:48
But we can do a little better than that.
01:50
So what if instead of both of our oxygen atoms being singly bonded, one of them was actually doubly bonded? and then we still have our two electrons on our central nitrogen atom.
02:02
What happens to the formal charges now? well, now the oxygen atom on the right has a formal charge of zero because we have 6 minus 4 minus 2.
02:13
So that has a formal charge of 0.
02:15
And the central nitrogen atom now has a formal charge of 5 minus 2 minus 3.
02:21
So that's a formal charge of 0.
02:23
And then we just have the formal charge of minus 1 on the oxygen atom on the left.
02:27
So by getting our formal charges on more atoms to be 0 ,000.
02:31
We came up with a better lewis structure.
02:35
But this is actually, this lewis structure is what we call resonant stabilized.
02:39
So there's a different way of writing this and an equivalent structure.
02:44
We could have the doubly bonded oxygen atom as the atom on the left rather than the atom on the right.
02:54
And these two structures are equivalent.
02:58
So which one is actually going to be the structure? which one's going to have a double bond and which one's going to have a double bond and which one's going to going to have a single bond.
03:06
Well, what actually happens, because these two structures are equivalent, the structure, the true structure will be an average of them.
03:15
So the true bond lengths for both of these no bonds will be somewhere between a single bond and somewhere between a double bond because of this resonant stabilization.
03:24
So what about no3 minus? well, we know our nitrogen brings five valence electrons, then we have three oxygen atoms, each bringing six valence electrons.
03:32
Our overall charge is minus one, so we have one extra...